2(5n-2)=4(n+2)
10n-4=4n+8
6n-4=8
6n=12
n=2
Answer:
71.123 mph ≤ μ ≤ 77.277 mph
Step-by-step explanation:
Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:
≤ μ ≤ 
Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and
is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.
the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.
So, if we replace m by 74.2, s by 5.3083, n by 10 and
by 1.8331, we get that the 90% confidence interval for the mean speed is:
≤ μ ≤ 
74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077
71.123 ≤ μ ≤ 77.277
Answer:
"0.0373" seems to be the appropriate solution.
Step-by-step explanation:
The given values are:
n₁ = 43
n₂ = 35




Now,
The test statistic will be:
⇒ 
On substituting the given values in the above formula, we get
⇒ 
⇒ 
⇒ 
⇒ 
then,
P-value will be:
= 
= 
Answer:
Adjacent
Step-by-step explanation:
Vertical would be 90 degrees
Answer:
Cuanto dinero voy a pagar 24 $
Cuanto recibiré de cambio 76 $
Step-by-step explanation:
Mis compras son:
1 lápiz 3,50 $
2 plumas 7,90 $
1Libreta 12,60 $
Lo que quiere decir que compre:
3,50 + 7,90 + 12,60 = 24 $
Si cancelo mis compras con un billete de 100 $ me tienen que dar vuelto por:
100 $ - 24 $ = 76 $