The sum of the two smaller sides must be greater than longest side.
A) 3+2 > 7 ..... False
B) 6+10 > 14 ... True
C) 3+2 > 5 ....False
D) 23+18 > 42 ....False
Answer is B
Well you would take 53% then put it over 100 so you should get 53/100
Answer:
NA
a = 53
Step-by-step explanation:
A bisector creates two equal angles. Set them equal to each other.
5a - 160 = 2a - 1 ( subtract 2a from both sides)
3a = 159 (add 159 to both sides)
a = 53 (divide by 3)
Part 1: Answer:
(x+1)(x+1)(x-6) = x^3 - 4x^2 - 11x - 6
Step-by-step explanation:
To make r a root, include (x-r) as a factor. (-1+1)(-1+1)(-1-6) is zero even though (-1-6) isn't.
(6+1)(6+1)(6-6) is zero.
Part 2 Answer:
Standard form: y = -x^4 + 12
Degree 4
left end goes down, right end goes down.
Step by step: apply the definitions of standard form, polynomial degree, and "end behavior". In other words, read the textbook.
Part 3: Answer: x = 3, x = 8
Step by step:
x^2-11x = -24
x^2-11x+24 = 0
(x-3)(x-8) = 0
x = 3 or x = 8
Part 4a Answer:
quotient 2x^2 + x - 3
remainder 1
Step by step:
2x^2 + x - 3
___________________
x-4 ) 2x^3 - 7x^2 - 7x + 13
2x^3 - 8x^2
__________
0 + x^2 - 7x + 13
x^2 - 4x
____________
0 - 3x + 13
- 3x + 12
______
1
Part 4b answer:
quotient 2x^2 - 6x + 2
remainder -20
Step by step: you have to know exactly what you are doing. Refer to textbook or Wikipedia.
dividend 2x^3 +14x^2 - 58x
divisor x+10
leading coefficient of divisor must be 1
write coefficients of dividend at top
write coefficients of dividend at left
| 2 14 -58 0
-10 | -20 60 -20
___________
| 2 -6 2 -20
Coefficients of quotient are 2 -6 2
Remainder is -20
quotient = 2x^2 - 6x + 2
Answer:
Whether you're teaching the meaning of fractions or fraction operations, visual models can help students connect fractions to what they already know. Division is an essential foundation for fractions. Once students can divide objects into equal groups, they can begin to grasp dividing a whole into equal parts.
Step-by-step explanation: