![{ \qquad\qquad\huge\underline{{\sf Answer}}}](https://tex.z-dn.net/?f=%7B%20%5Cqquad%5Cqquad%5Chuge%5Cunderline%7B%7B%5Csf%20Answer%7D%7D%7D%20)
Let's proceed according to Bodmas rule ~
![\qquad \sf \dashrightarrow \:9 - 3 \div \frac{1}{3} 1](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A9%20-%203%20%5Cdiv%20%20%5Cfrac%7B1%7D%7B3%7D%201)
[ as 3 ÷ 1/3 = 3 × 3 = 9 ]
![\qquad \sf \dashrightarrow 9 - 9](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%209%20-%209)
![\qquad \sf \dashrightarrow \:0](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A0)
So, by simplification we will get 0 as our result.
Answer:
75
Step-by-step explanation:
Total number of students = 35
Nø of chocolate received by each student = 2
Number of chocolates = 35 * 2 = 70
After the distribution of chocolate, remaining chocolates = 5
Then Now
Total chocolates = 70 + 5 = 75
Hope it will help :)
Answer:
The answer is...
Step-by-step explanation:
<em><u>CAN'T JOIN ANYMORE.</u></em>
Add 8 to both sides
x - 8 + 8 < -1 + 8
x < 7
Answer:
Step-by-step explanation:
The second and third functions are linear, since both x and y are to the first power.
The first function is cubic and does n ot count here.
The last function seems to involve the square root, and also does not count.