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vredina [299]
3 years ago
10

Lines a and b are perpendicular. The slope of line a is −2. What is the slope of line b?

Mathematics
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

1/2

Step-by-step explanation:

When two lines whose scopes are m₁ and m₂ are perpendicular, then the product of the scopes of both lines is -1.

Therefore,

If m₁ is the scope of line a and m₂ is the scope of line b then,

m₁m₂ = -1 and m₁ = -2

-2m₂ = -1

m₂ = -1/-2 = 1/2

The slope of line b is 1/2.

fiasKO [112]3 years ago
3 0

b= 1/2

perpendicular slopes are those that are opposite signs and reciprocal of the original given slope

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earnstyle [38]

Answer:

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8(w + 2 ) = 7

3 0
2 years ago
10 1/16ft + 8 3/8ft +1/2 ft
Whitepunk [10]

Answer:

18 15/16 ft

Step-by-step explanation:

what is the request here ?

to do the additions and bring all to one summary result of ft ?

I base my answer on this assumption.

10 1/16 = 161/16

8 3/8 = 67/8

1/2 = 1/2

note let's bring everything to 16th, so that we can actually add them.

161/16

67/8 = 134/16

1/2 = 8/16

161/16 + 134/16 + 8/16 = 303/16 = 18 15/16

cross check :

add all whole numbers first, and then add the remaining fractions too (need to bring them to 16th too).

10 + 8 = 18

1/16 + 3/8 + 1/2 = 1/16 + 6/16 + 8/16 = 15/16

together, 18 15/16

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6 0
3 years ago
Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park: A coordinate plane is shown.
Nostrana [21]

Question:

Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park.There is a point at (−6, 3) labeled Dog 1. There is a point at (−6, −3) labeled Dog 2.

Which statement best describes the relationship between the positions of the two players?

A.Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

B.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

C.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

D. Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

Answer:

Option B: Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

Explanation:

The position of the Dog 1 is (−6, 3).

The position of the Dog 2 is (−6, -3).

From the graph, we can see that the image of Dog 1 is reflected over x-axis. Because to reflect an image over x-axis, the signs of y-coordinate must be changed.

Hence, Option B is correct.

Thus, Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

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Step-by-step explanation:


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