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The answer is:
4x+2y=11} 4x+2y=11} x=2-2y
x-2=-2y } x+2y=2 } x=2-2(-3/6)
x=2-(-6/6)
4(2-2y)+2y=11 x=2-(-1)
8-8y+2y=11 x=3
8-6y=11
-6y=11-8
-6y=3/-6
y=-3/6=-1/2
So for my opinion the solution is A.(3,-1/2)
Answer:
<h2><u>
50 ft³</u></h2>
Step-by-step explanation:
We know the formula for a rectangular prism is length × width × height
We also know all the sides so we can rewrite the formula replacing variables.
The length is 8, the width is 2
and the height is 2
8 × 2
× 2
Multiply which ever way is easy for you. I am just multiplying from left to right.
8 × 2
= 20
20 × 2
= 50
Now we get 50. Before we put our answer as 50, there are two more steps.
First we need to add the measurement unit which is feet or ft
We also need to add ³ since it is volume
<u>50 ft³ is our final answer</u>
Answer:
16, 24
Step-by-step explanation:
1 List the factors of each number.
Factors of 16 : 1, 2, 4, 8, 16
Factors of 24 : 1, 2, 3, 4, 6, 8, 12, 24
2 Find the largest number that is shared by all rows above. This is the GCF.
GCF = 8
m x H = ![\left[\begin{array}{ccc}-25&37.5&-12.5\\\9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%2637.5%26-12.5%5C%5C%5C9%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Step 1; Multiply 5 with this matrix
and we get a matrix ![\left[\begin{array}{ccc}-5&10\\20&40\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%2610%5C%5C20%2640%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiply the fraction
with the matrix
and we get ![\left[\begin{array}{ccc}-\frac{2m}{5} &\frac{4m}{5} \\\frac{8m}{5} &\frac{16m}{5} \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-%5Cfrac%7B2m%7D%7B5%7D%20%26%5Cfrac%7B4m%7D%7B5%7D%20%5C%5C%5Cfrac%7B8m%7D%7B5%7D%20%26%5Cfrac%7B16m%7D%7B5%7D%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step2; Now equate corresponding values of the matrices with each other.
-5 =
and so on. By equating we get the value of m as 
Step 3; Add the matrices to get the value of matrix m.
Adding the three matrices on the RHS we get
.
Step 4; Adding the matrices on the LHS we get the resulting matrix as H +
. Equating the matrices from step 3 and 4 we get the value of H as ![\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%263%26-1%5C%5C%5C9%5Cend%7Barray%7D%5Cright%5D)
Step 5; Now to find the value of m x H we need to multiply the value of
with the matrix
Step 6; Multiplying we get the matrix m x H = [ -25
]