Question

Find the area of this regular polygon round to nearest tenth

Answer 1

Answer:

$A=163.9in^2$

Step-by-step explanation:

Let's use the regular polygon area formula when given the radius.

$A=\frac{(r^{2})(n)sin(\frac{360}{n})}{2}$

r is radius

n is the number of sides

Let's plug in the proper values into this equation and simplify:

$A=\frac{(7.74^{2})(7)sin(\frac{360}{7})}{2}$

$A=\frac{(59.9076)(7)(0.78183148)}{2}$

$A=\frac{327.86353299}{2}$

$A=163.93176649$