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rosijanka [135]
3 years ago
6

Last season two running backs on the steelers football team rushed or a combined total of 1550 yards. One rushed 4 times as many

yards as the other. How many yards were rushed by each player
Mathematics
2 answers:
Papessa [141]3 years ago
8 0
60 yards is the answer
Ludmilka [50]3 years ago
5 0
60 yards is the answer
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Solve the the equation by substitution<br>5x=-2y+48<br>x=-3y+20​
tamaranim1 [39]

Answer:

(8, 4)

Step-by-step explanation:

i hope this helps :)

8 0
2 years ago
Mathmerica Bank offers 2.1% interest compounded yearly
Scilla [17]

Answer:

Total = 2,500 (1.021)^t

Step-by-step explanation:

There is no question but the formula for compound interest is

Total = amount (1 + rate)^time

Total = 2,500 (1.021)^t

6 0
3 years ago
Solve for (0,2π]<br> 2cos ß * sin ß = cos ß
Temka [501]

Given :

An equation, 2cos ß sin ß = cos ß .

To Find :

The value for above equation in (0, 2π ] .

Solution :

Now, 2cos ß sin ß = cos ß

2 sin ß = 1

sin ß = 1/2

We know, sin ß = sin (π/6)  or sin ß = sin (5π/6) in  ( 0, 2π ] .

Therefore,

\beta = \dfrac{\pi}{6}\ or\ \beta = \dfrac{5\pi}{6}

Hence, this is the required solution.

4 0
2 years ago
Limit question: lim x--&gt;pi ((e^sinx)-1)/(x-pi)
aleksandr82 [10.1K]
\displaystyle\lim_{x\to\pi}\dfrac{e^{\sin x}-1}{x-\pi}

Notice that if f(x)=e^{\sin x}, then f(\pi)=e^{\sin\pi}=e^0=1. Recall the definition of the derivative of a function f(x) at a point x=c:

f'(c):=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}

So the value of this limit is exactly the value of the derivative of f(x)=e^{\sin x} at x=\pi.

You have

f'(x)=\cos x\,e^{\sin x}\implies f'(\pi)=\cos\pi\,e^{\sin\pi}=-1
4 0
3 years ago
In which quadrants do solutions for the inequality y is less than or equal to two sevenths times x plus 1 exist? i, iii, and iv
tigry1 [53]

The solutions will lie  in all the four quadrants.

y≤2/7x+1

We have the following inequality:

y=2/7x+1

If x=0

y=2/7(0) +1

y=1

If y=0

x=-3.5

So the line passes through the points:

(0,1) and (-3.5,0)

To find the shaded region, let us take a point, namely, the origin and test it in the inequality:

y≤ 2/7x +1

0≤ 2/7(0) +1

0≤ 1 which is true

Since this is true, then the shaded region includes this point. This is shown below and as you can see the solutions exist in all four quadrants.

To learn more about Inequalities, visit brainly.com/question/12890742

#SPJ4

4 0
2 years ago
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