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9966 [12]
3 years ago
11

Select all of the expressions that are equivalent to -7.

Mathematics
1 answer:
Ivanshal [37]3 years ago
6 0

Answer:

the answers that are equivalent are a, b, and e

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Need some help with this one!!!
muminat

Answer:

210

Step-by-step explanation:

2 x 3 x 5 x 7 = 210

4 0
2 years ago
I NEED HELP XDDD what is 36 = 4x = ?
Mice21 [21]

Answer:

x = 9

Step-by-step explanation:

divide both sides of the equation by 4 to isolate the x variable according to algerba. Hope it helps!

6 0
2 years ago
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Shailes class had 2 students out of 5 students choose Fortnite as their favorite video game. What was the
GuDViN [60]

Answer:

<em>40%</em>

Step-by-step explanation: <em>2 divided by 5 is 0.4 so that is 40%</em>

6 0
3 years ago
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A slide 4.4 m long makes an angle of 33 with the ground. How high is the top of the slide above the ground
svp [43]
Using the information given we will only need the Cosine and Sine equations.  i made a diagram (cant take a picture, in my study hall) labeled the sides of the triangle A, B, and C.  with C as the hypotenuse, A as the Opposite, and B as the adjacent (will not be needed as A is the height). i will be rounding the th nearest thousandth. 
Using Sine (SIN=Opposite/Hypotenuse), we can find A.

SIN(33)=A/4.4

SIN(33)≈.545

.545≈A/4.4

now multiply each side by 4.4 to get rid of the division

(.545*4.4)≈((A/4.4)4.4)

2.396≈A
 

so the answer would be that the slide is about 2.396 M high
5 0
3 years ago
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

 = 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

6 0
3 years ago
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