Answer:
❤️
Step-by-step explanation:
Answer:
this is to hard and I like math
Answer:
Barbara's speed in clear weather is
and in the thunderstorm is
.
Step-by-step explanation:
Let
be the speed and
be the time Barbara drives in clear weather, and let
be the speed and
be the time she drives in the thunderstorm.
Barbara drives 22 mph lower in the thunderstorm than in the clear weather; therefore,
(1). ![v_2 = v_1 -22](https://tex.z-dn.net/?f=v_2%20%3D%20v_1%20-22)
Also,
(2).
(3).
,
and
(4). ![t_1+t_2 = 2.25hr](https://tex.z-dn.net/?f=t_1%2Bt_2%20%3D%202.25hr)
From equations (2) and (3) we get:
![t_1 = \dfrac{45}{v_1}](https://tex.z-dn.net/?f=t_1%20%3D%20%5Cdfrac%7B45%7D%7Bv_1%7D)
![t_2 =\dfrac{57}{v_2}](https://tex.z-dn.net/?f=t_2%20%3D%5Cdfrac%7B57%7D%7Bv_2%7D)
putting these in equation (4) we get:
![\dfrac{45}{v_1}+\dfrac{57}{v_2}=2.25](https://tex.z-dn.net/?f=%5Cdfrac%7B45%7D%7Bv_1%7D%2B%5Cdfrac%7B57%7D%7Bv_2%7D%3D2.25)
and substituting for
from equation (1) we get:
![\dfrac{45}{v_1}+\dfrac{57}{v_1-22}=2.25](https://tex.z-dn.net/?f=%5Cdfrac%7B45%7D%7Bv_1%7D%2B%5Cdfrac%7B57%7D%7Bv_1-22%7D%3D2.25)
This equation can be rewritten as
![2.25v_1^2-151.5v_1+990=0](https://tex.z-dn.net/?f=2.25v_1%5E2-151.5v_1%2B990%3D0)
which has solutions
![v_1 = 60](https://tex.z-dn.net/?f=v_1%20%3D%2060)
![v_1 = 7.33](https://tex.z-dn.net/?f=v_1%20%3D%207.33)
We take the first solution
because it gives a positive value for ![v_2:](https://tex.z-dn.net/?f=v_2%3A)
![v_2 = v_1 -22](https://tex.z-dn.net/?f=v_2%20%3D%20v_1%20-22)
![v_2 = 60 -22\\](https://tex.z-dn.net/?f=v_2%20%3D%2060%20-22%5C%5C)
.
Thus, Barbara's speed in clear weather is
and in the thunderstorm is
.
Answer:
C+3
Step-by-step explanation: