Wait please help I’m so confused

Mathematics

1 answer:

kkurt [141]2 years ago

8 0

X=7 since you need to make an equation and in one hour you make $7. Don’t include the 1 as in 1x cause that’s incorrect

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What is 50,000 times 10 to the 15th

Misha Larkins [42]

Remember property of exponents
$(x^m)(x^n)=x^{m+n}$
add exponents of same base

ok so

50,000 is 5 times 10^4

so

50000 times 10^15=
5 times 10^4 times 10^15=
5 times $10^{4+15}$ =
5 times 10^19

8 0

2 years ago

Find the greatest common factor and the least common multiple of 16 and 20. The prime factorizations of each number are given.

kykrilka [37]

Answer:

GCF 4, LCM 80

Step-by-step explanation:

Since both 16 and 20 have two 2s as factor, their greatest common factor is 4.

The LCM is found by multiplying all of the remaining factors by the LCM:

16 still has (2 x 2), 20 still has (5), times the GCF (4) so 2 x 2 x 5 x 4 = 80.

5 0

1 year ago

Find an equation for the perpendicular bisector of the line segment whose endpoints

TEA [102]

Answer:

y= -2x -8

Step-by-step explanation:

I will be writing the equation of the perpendicular bisector in the slope-intercept form which is y=mx +c, where m is the gradient and c is the y-intercept.

A perpendicular bisector is a line that cuts through the other line perpendicularly (at 90°) and into 2 equal parts (and thus passes through the midpoint of the line).

Let's find the gradient of the given line.

$\boxed{gradient = \frac{y1 -y 2}{x1 - x2} }$

Gradient of given line

$= \frac{1 - ( - 5)}{3 - ( - 9)}$

$= \frac{1 + 5}{3 + 9}$

$= \frac{6}{12}$

$= \frac{1}{2}$

The product of the gradients of 2 perpendicular lines is -1.

(½)(gradient of perpendicular bisector)= -1

Gradient of perpendicular bisector

= -1 ÷(½)

= -1(2)

= -2

Substitute m= -2 into the equation:

y= -2x +c

To find the value of c, we need to substitute a pair of coordinates that the line passes through into the equation. Since the perpendicular bisector passes through the midpoint of the given line, let's find the coordinates of the midpoint.

$\boxed{midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2}) }$