Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Answer:
1/27
Step-by-step explanation:
There are 9 numbers between 0 and 8. 3 of them are less than 3 (0, 1, and 2), and 1 of them is 6.
The probability is therefore (3/9) (1/9) = 1/27.
I believe it’s the last one
Answer is 9r
Because 9x3 is 27
Also no clue about the brainliest thing
