What is greather 1 mi 2,000 yd

1.

creativ13 [48]

If the diameter is 12 inches, the radius is 6 inches, because the radius is half the diameter.

Given the formula

$A=\pi r^2$

we have

$A=36\pi$

When you fold the circle in half, the resulting figure has half the area.

So, you start with a circle with area $36\pi$

You fold it once and you have a semicircle with area $18\pi$

You fold it twice and you have a quarter circle with area $9\pi$

7 0

3 years ago

The drawing below (not to scale) shows a running track. The ends are semicircles. The distance between the two inner parallel st

aleksklad [387]

We are looking for the inner perimeter of the track. Since there are two semicircles, these mix to form one full circle so we can use the formula to find the circumference of the circle with a diameter of 60 m, which was given to us. With a diameter of 60m, the radius will be 30m. Now we can solve this problem.
C = 2πr
C = 2π(30)
C = 60π
The semicircle ends of the track are a distance of 60π m, and now we just need to add the lengths of the inner track which are 100 m each. So:
P = 60π + 100m + 100m
P = 200 + 60π
P = 388.5 m

4 0

3 years ago

The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that

wlad13 [49]

Answer:

a) 0.0821

b) 0.0111

c) 0.0041

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \lambda e^{-\lambda x}$

In which $\lambda$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\lambda x}$

Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

In all 3 cases, we want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = 1 - e^{-5\lambda}$

(a) lambda=.5

$P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821$

(b) lambda=0.9

$P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111$

(c) lambda=1.1

$P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041$

7 0

4 years ago

I have zero idea.. help please.

r-ruslan [8.4K]

As we look, line TU = 16. But, there are two lines right below it, and there are two lines on the line UW. Now, all that this means is UW is the same length as TU.

Since we know what TU and UW is and we need to add them together to find the total length of the line TW.

16 + 16 = 32.

Therefore, the length of line TW is 32 units long.

Hope I could help you out!
If my answer is incorrect, or I provided an answer you were not looking for, please let me know. However, if my answer is explained well and correct, please consider marking my answer as Brainliest! :)

Have a good one.
God bless!

8 0

3 years ago

Read 2 more answers

Give the slope of a line parallel to the given line.

cluponka [151]

Answer:

y=2x+ 4

Step-by-step explanation:

Same slopes and different y-intercept are parallel lines

8 0

3 years ago