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4 years ago

15

Help please........................

1 answer:

yawa3891 [41]4 years ago

7 0

A dilation means that a shape is expanded or shrunk by a scale factor. The scale factor is 4, so all the points are multiplied by 4 to reflect this expansion.

A reflection over the y-axis means that the y-values in the points change their sign from positive to negative, and vice versa.

Therefore, the points will become the following:
A''(12,-12), B''(-4, -12), C''(-16,-4), D''(0, -4)

This new shape will be similar to the original shape, since it shares the same shape, but not the same size.

The answer is A.

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The best interest rate for a borrower on a $5,000 loan for 5 years is:

Gennadij [26K]

Answer:

So, $83.40 should be paid monthly

Step-by-step explanation:

5000 divided by 5 = 1000

1000 should be paid yearly

1000 divided by 12 = 83.40

12 represents the number of months in a year.

3 0

3 years ago

Read 2 more answers

Slope is –2 & (5, 3) is on the line.<br> Y-Intercept:<br> Equation of the line (no spaces):

GREYUIT [131]

Answer:

The y intercept is (0,13)

The equation of the line is y = -2x+13

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -2x+b

Substituting the point

3 = -2(5) +b

3 = -10 +b

Add 10 to each side

13 =b

The y intercept is (0,13)

The equation of the line is y = -2x+13

5 0

3 years ago

(SSS, SAS, AAS, ASA, HL)<br><br> Help me plzzzz

-Dominant- [34]

The answer is HL. We know this because it is a right triangle (:

7 0

3 years ago

In a right triangle, the acute angles measure ×+15 and 2× degrees. What is the measure of the larger acute angle of the triangle

harkovskaia [24]

Sum of angles in a triangle is 180°

90 + (x + 15) + (2x) = 180

90 + x + 15 + 2x = 180

105 + 3x = 180

3x = 180 - 105

3x = 75

x = 75 ÷ 3

x = 25

Smaller angle = x + 15 = 25 + 15 = 40°

Larger angle = 2x = 2(25) = 50°

Answer: 50°

5 0

4 years ago

If f(x)=ln(sin(2x)), f''(π/4) is equal to

Licemer1 [7]

Use the chain rule to compute the second derivative:

$f(x)=\ln(\sin(2x))$

The first derivative is

$f'(x)=(\ln(\sin(2x)))'=\dfrac{(\sin(2x))'}{\sin(2x)}=\dfrac{\cos(2x)(2x)'}{\sin(2x)}=\dfrac{2\cos(2x)}{\sin(2x)}$

$f'(x)=2\cot(2x)$

Then the second derivative is

$f''(x)=(2\cot(2x))'=-2\csc^2(2x)(2x)'$

$f''(x)=-4\csc^2(2x)$

Then plug in π/4 for <em>x</em> :

$f''\left(\dfrac\pi4\right)=-4\csc^2\left(\dfrac{2\pi}4\right)=-4$

4 0

3 years ago