Answer:
I know that the first is true and the last one is false i am trying to help you if i know others i wiil tell you
Joey borrowed the money for 4 months. 2000 multiplied by .05 comes out to 100 which is the 5% so for him to get to 400 he had to owe the money for 4 months to pay 400 in interest. Hope this helps.
1) -3•5/ 4•5 And 9•2/ 10•2 Because you want to have the same denominator. That equals -15/20 + 18/20 so you just add -15+18 to get 3/20
The answer is 3/20
Answer:
0.0094.
Step-by-step explanation:
For the given experiment, let X be the lifetimes of parts manufactured from a certain aluminum alloy.
sample size =73
Sample mean = 784
Sample standard deviation = 120
Let µ represent the mean number of kilocycles to failure for parts of this type.
Null hypothesis, H0 : µ ≤ 750
Alternative hypothesis, H1 : µ > 750.
![z=\dfrac{\overline{X}-\mu}{\frac{s}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D%7D)
where,
is sample mean.
is population mean.
s is sample standard deviation.
n is the sample size.
![z=\dfrac{783-750}{\frac{120}{\sqrt{73}}}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B783-750%7D%7B%5Cfrac%7B120%7D%7B%5Csqrt%7B73%7D%7D%7D)
![z=2.35](https://tex.z-dn.net/?f=z%3D2.35)
It is a right tailed test because alternative hypothesis is µ > 750. So, P-value is the probability of observing a sample mean greater that 783 or the probability of P(z>2.35).
![P=P(z>2.35)](https://tex.z-dn.net/?f=P%3DP%28z%3E2.35%29)
![P=1-P(z](https://tex.z-dn.net/?f=P%3D1-P%28z%3C2.35%29)
![P=1-0.9906](https://tex.z-dn.net/?f=P%3D1-0.9906)
![P=0.0094](https://tex.z-dn.net/?f=P%3D0.0094)
Therefore the P-value is 0.0094.
Answer:
Step-by-step explanation:
Since we do not know the base of the logarithm, then we must take the area of permissible expressions, then we denote n as the base ; then n ≠1 ; n>0
![\boldsymbol {Rule} : \\\\ \boldsymbol {\log _ n a+\log _n b = \log _n a\cdot b} \\\\ \boldsymbol {n \cdot \log _a b =\log_a b ^n } \\\\ \large \boldsymbol {} \log _n (x+y)= \log_n 3 + \frac{1}{2} \log_n x+\frac{1}{2} \log _n y \\\\ \log _n (x+y) = \log _n 3+\frac{1}{2} (\log_n xy ) \\\\ \log _n ( x+y ) = \log_n 3+\log _n \sqrt{xy } \\\\ \log _n (x+y) = \log_n \ 3 \sqrt{xy } \\\\ x+y= 3\sqrt{xy} \\\\ (x+y) ^2= (3\sqrt{xy} })^2 \\\\ x^2+y^2+2xy =9 xy \\\\ \boldsymbol {x^2+y^2=7xy }](https://tex.z-dn.net/?f=%5Cboldsymbol%20%7BRule%7D%20%3A%20%5C%5C%5C%5C%20%20%5Cboldsymbol%20%7B%5Clog%20_%20n%20a%2B%5Clog%20_n%20b%20%3D%20%5Clog%20_n%20a%5Ccdot%20b%7D%20%5C%5C%5C%5C%20%5Cboldsymbol%20%7Bn%20%5Ccdot%20%5Clog%20_a%20b%20%3D%5Clog_a%20b%20%5En%20%20%20%7D%20%5C%5C%5C%5C%20%5Clarge%20%5Cboldsymbol%20%7B%7D%20%5Clog%20_n%20%28x%2By%29%3D%20%5Clog_n%20%203%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Clog_n%20%20x%2B%5Cfrac%7B1%7D%7B2%7D%20%5Clog%20_n%20y%20%20%20%5C%5C%5C%5C%20%5Clog%20_n%20%28x%2By%29%20%3D%20%5Clog%20_n%203%2B%5Cfrac%7B1%7D%7B2%7D%20%28%5Clog_n%20%20xy%20%20%29%20%20%5C%5C%5C%5C%20%5Clog%20_n%20%28%20x%2By%20%29%20%3D%20%5Clog_n%20%203%2B%5Clog%20_n%20%5Csqrt%7Bxy%20%7D%20%20%5C%5C%5C%5C%20%5Clog%20_n%20%28x%2By%29%20%3D%20%5Clog_n%20%20%20%5C%203%20%20%5Csqrt%7Bxy%20%7D%20%20%5C%5C%5C%5C%20x%2By%3D%203%5Csqrt%7Bxy%7D%20%5C%5C%5C%5C%20%28x%2By%29%20%5E2%3D%20%283%5Csqrt%7Bxy%7D%20%7D%29%5E2%20%5C%5C%5C%5C%20x%5E2%2By%5E2%2B2xy%20%3D9%20xy%20%20%5C%5C%5C%5C%20%5Cboldsymbol%20%7Bx%5E2%2By%5E2%3D7xy%20%7D)