c) Combine 2+3 to get 5. 100-(5x5) equals 100-25. 100-25 is 75. The answer is 75.
d) Combine 2+3 to get 5. Combine 1+4 to get 5, which is 25. The answer is 5.
g) Combine 4+6 to get 10. Combine 70+-6 to get 64. Take the root of 64, leaving you with 10-8. Combine 10 + -8 to get 2. The answer is 2.
h) Combine 5+4 to get 9. Take the root of 36, leaving you with 18 + 6. Combine 18 + 6 to get 24. The answer is 24.
5. [15 + 22 + 53] divided by [12 + 18] = [90] divided by [30] = 3 ribbons each.
6. (4 x 12) + (6 x 8) = 96 total.
Answer: 4 Mph.
Step-by-step explanation: ...
Answer:
Part 1) The trapezoid has an area of 
Part 2) The kite has an area of 
Part 3) The area of the trapezoid is less than the area of the kite
Step-by-step explanation:
Part 1
Find the area of trapezoid
we know that
The area of trapezoid is equal to the area of two congruent triangles plus the area of a rectangle
so
![A=2[\frac{1}{2} (2)(5)]+(2)(5)](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%20%282%29%285%29%5D%2B%282%29%285%29)
Part 2
Find the area of the kite
we know that
The area of the kite is equal to the area of two congruent triangles
so
![A=2[\frac{1}{2} (7)(3)]=21\ m^2](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%20%287%29%283%29%5D%3D21%5C%20m%5E2)
Part 3
Compare the areas
The trapezoid has an area of
The kite has an area of
so
therefore
The area of the trapezoid is less than the area of the kite
Average rate of change can be calculated by determining the
rate of change at x = a, and at x = b
f’(x) =2 (3^x) ln(3)
f’(0) = 2 ln(3)
f’(1) = 6 ln(3)
f’(2) = 18 ln(3)
f’(3) = 54 ln(3)
Average:
at section A = [6 ln(3) – 2 ln(3)]/1 = 4 ln(3)
at section B = [54 ln(3) – 18 ln(3)]/1 = 36 ln(3)
section B is 9 times larger.
Based from the f’(x), f’(x) varies as the power of x. so the
greater of value of x, the greater the rate of change.
