Answer:
Step-by-step explanation:
<u>According to the question we have:</u>
- Formula h = - 16t + s
- h = 0
- s = 555.427 ft
- t = ?
<u>Substitute the given values and solve for t:</u>
- 0 = - 16t + 555.427
- 16t = 555.427
- t = 555.427/16
- t = 34.714
Answer:
Wheres the table?
Step-by-step explanation:
Answer:
The 99% confidence interval for the proportion of athletes who graduate is (0.5309, 0.7323).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 152, \pi = \frac{96}{152} = 0.6316](https://tex.z-dn.net/?f=n%20%3D%20152%2C%20%5Cpi%20%3D%20%5Cfrac%7B96%7D%7B152%7D%20%3D%200.6316)
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6316 - 2.575\sqrt{\frac{0.6316*0.3684}{152}} = 0.5309](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.6316%20-%202.575%5Csqrt%7B%5Cfrac%7B0.6316%2A0.3684%7D%7B152%7D%7D%20%3D%200.5309)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6316 + 2.575\sqrt{\frac{0.6316*0.3684}{152}} = 0.7323](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.6316%20%2B%202.575%5Csqrt%7B%5Cfrac%7B0.6316%2A0.3684%7D%7B152%7D%7D%20%3D%200.7323)
The 99% confidence interval for the proportion of athletes who graduate is (0.5309, 0.7323).
Answer:
21
Step-by-step explanation:
The cube root of 9.261 is 2.1 because 2.1 × 2.1 × 2.1 = 9.261.
Per day : 7.5hrs
5days : 37.5hrs
7days : 52.5hrs