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AysviL [449]
3 years ago
5

You may have learned about the sheep clone, Dolly, in your science class. Although this experiment was greeted as a great succes

s, there are many problems with cloning. One of the ethical issues surrounding cloning has to do with the success rate of the process. This is because
A) cloning has never been and never will be possible.
B) cloning has become too successful in recent years.
C) cloning mammals has a very low success rate, and can produce severely damaged young.
D) cloning mammals has a very high success rate, and can produce severely damaged young.
Biology
2 answers:
o-na [289]3 years ago
7 0

Answer:

C) cloning mammals has a very low success rate, and can produce severely damaged young.

Explanation:

Cloning of mammals has a very low success rate and can produce severely damaged pups. Proof of this was what happened to the Dolly sheep.

The cloning that gave rise to Dolly is also called "nucleus transfer", that is, the nucleus of a somatic cell is removed and placed in an egg whose nucleus was previously removed. This cell is capable of dividing and, if the resulting embryo is implanted in a uterus and succeeds in developing, it can generate an individual. Interesting, or scary, was knowing that 276 attempts were made until Dolly was born, and most of the eggs used, with the nucleus changed, did not even divide. And that of all the other embryos that managed to divide and be implanted, only Dolly was born. All others died during pregnancy, many of them with genetic alterations or severe malformations.

On February 14, 2003, at the age of six and a half, Dolly underwent a lethal injection, as she was the victim of a serious lung disease, of supposedly infectious origin. The scientific community still expects further explanations about the disease that affected the most famous sheep in the world. Could this disease be caused by a genetic error resulting from cloning? Dolly's "breeders", Scottish researchers at the Roslin Institute, said the disease is common in sheep and was probably acquired. But how could Dolly have been exposed to a very serious and fatal disease? It seems strange. In addition, Dolly had previously presented other problems possibly related to cloning. She was big, obese and lived in confinement. She had three pregnancies and six puppies. At just over five and a half years old, information was released that Dolly suffered from arthritis in her left hind leg.

Both arthritis and lung disease presented by Dolly are diseases characteristic of elderly sheep. Arthritis, in particular, was attributed to the fact that Dolly stood on her hind legs for a long time to "play" with visitors. But many vets dispute that justification. The hypothesis that has been discussed is that these diseases, common in older animals, could be associated with the shortening of telomeres (DNA sequences that are at the tip of chromosomes). It is already well known that chromosomes decrease in size and lose small portions of their genetic material over time. When Dolly was three years old, her telomeres were characteristic of a nine-year-old animal, the age that the nucleus donor would have if it were alive. However, this information is not confirmed by its creators, who dispute the results of these tests because they were done only once, in blood tissue. In addition, other cloned animals did not show shortening of telomeres.

Rina8888 [55]3 years ago
5 0
C. Cloning mammals has a very low success rate and can produce damaged young
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Match each type of cell junction with its description.
Ne4ueva [31]

Answer:

Tight junctions - prevent liquid from seeping between cells

Desmosomes - act as rivets to hold adjacent cells together when epithelial tissue moves

Gap junctions - allow movement of cytosol, ions, and small molecules between animal cells

Plasmodesmata - openings through the cell walls of plant cells that allow adjacent cells to share materials

Explanation:

1) Tight junctions are one of the cell junctions found in animal cells. Tight junctions function to prevent the flow of liquid materials between cells.

2) Desmosomes are another type of cell junctions whose function is to form a connection between two adjacent cells. The structure formed by this connection confers strength upon the tissues involved.

3) Gap junctions are the most commonly found cell junctions found in animal cells that connects adjacent cells allowing the passage of cytosol, ions and other small molecules in them from one adjacent cell to another.

4) Plasmodesmata is a cell junction found in plant cells. They are small openings lying across the cell wall of plant cells whose function is to connect the cells and facilitate the movement of materials from one cell to another.

7 0
3 years ago
An additional gene, gene W, was also examined. A test cross was made between true-breeding EEWW flies and EEWW flies. The result
Debora [2.8K]

This question is incorrect but here is the correct question below;

An additional gene,gene W was also examined. a test cross was made between true breeding EEWW flies and eeww flies. The resulting F₁ generation was then crossed with eeww flies. 100 offspring in the F₂ generation were examined and it was discovered that the E and W genes were not linked.

Which is the correct genotype of the F₂ offspring if the genes were linked and if the genes were not linked?

a) Linked: 50% EeWw and 50% eeww; not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

b) Linked: 25% Eeww, 50% eeWw; not linked:parental genotypes EeWw and eeww.

c) Linked genotypes (EeWw and eeww) and recombinant genotype ( Eeww & eeWw) in the F₂ generation are nearly the same irrespective of their linkage.

d) Linked: mostly with parental genotypes, Eeww and eeWw; unlinked: 25% EeWw and eeww with 75% Eeww and eeWw.

Answer:

a) Linked: 50% EeWw and 50% eeww; not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

Explanation:

a test cross was made between true breeding EEWW flies and eeww flies

If EEWW self crossed, we have the following ( EW, EW, EW, EW)

Also, for eeww, we have ( ew, ew, ew, ew)

                   

                    EW                   EW                     EW                   EW

ew               EWew               EWew               EWew               EWew      

ew               EWew               EWew               EWew               EWew

ew               EWew               EWew               EWew               EWew

ew               EWew               EWew               EWew               EWew

All offspring are  (EWew)

The question goes further by saying "The resulting F₁ generation was then crossed with eeww flies".

And we are asked to find the correct genotype of the F₂ offspring if the genes were linked and if the genes were not linked

∴

To determine  the offsprings of the linked genes we need to go by the definition and understand what linked genes are: Linked genes are genes that are physically close together on the same chromosomes. Effect of recombinantion on linked genes, results in gene swaps which occur in chromosomes that are homologous.

Having said that; If  EWew × eeww

we have;                 EW   &   ew    ×    ew  &    ew

           EW               ew

ew       EeWw          eeww

ew       EeWw          eeww

offspring that

are linked in   ⇒     EeWw    EeWw     &      eeww      eeww

F₂   will be

\frac{1}{2} = 50% of EeWw of the total 100 offspring in the F₂ cross

\frac{1}{2} = 50% of eeww of the total 100 offspring in the F₂ cross

∴ Linked genes =  50% EeWw and 50% eeww.

For unlinked genes; If  EWew × eeww

if rearrangement occurs in EWew  and EWew self crossed, we have ( EW,Ew,eW,ew) as the traits needed for the unlinked gene F₂ crossing.

Also ewew will be (ew, ew, ew, ew).

                       EW                    Ew                    eW                    ew

ew                  EeWw               Eeww                eeWw                eeww

ew                  EeWw               Eeww                eeWw                eeww

ew                  EeWw              Eeww                 eeWw                eeww

ew                  EeWw              Eeww                 eeWw                eeww

We have the following results for the unlinked genes

\frac{1}{4} = EeWw  25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = Eeww   25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = eeWw   25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = eeww    25% of the total 100 offspring in the F₂ cross

∴ not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

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Sedbober [7]

Answer:

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Alkaline earth metals (in old chemistry this name applied only to Ca and its congeners)

Icosagens (unofficial name; aka Boron group; rarely Earth metals)

Crystallogens (unofficial name; aka Carbon group; rarely Adamantogens[a] or Merylides[b])

Pnictogens

Chalcogens

Halogens

Noble gases (rarely Aerogens). The Group name may have to be changed to the “Helium group” since oganesson is not expected to be noble.

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