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Zigmanuir [339]
3 years ago
6

Emily uses 1 2/3cups of sugar and 3 1/4cups flour to make muffins she says she has12/3 more cups of flour than sugar ​

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

what's the question?????

Step-by-step explanation:

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Rainbow [258]

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Step-by-step explanation:

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3 years ago
41. Which system is represented by the graph?
nekit [7.7K]

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the answer is the first choice please mark me brainliest

6 0
2 years ago
Andrea calls two truck rental companies to compare costs. Action trucks charges $80 for the day plus $0.22 per kilometer and tru
Amanda [17]

Answer:it will take 200 kilometers for the costs to be the same.

Step-by-step explanation:

Let x represent the number of kilometers that Andrea would have to drive for the total cost of renting from both companies to be the same.

Action trucks charges $80 for the day plus $0.22 per kilometer. It means that the total cost of x miles would be

80 + 0.22x - - - - - - - - - 1

Truck experts charges $100 for the day plus $0.12 per kilometer. It means that the total cost of x miles would be

100 + 0.12x - - - - - - - - - 2

Therefore, for the cost of renting from both companies to be the same,

80 + 0.22x = 100 + 0.12x

0.22x - 0.12x = 100 - 80

0.1x = 20

x = 20/0.1 = 200

4 0
3 years ago
What number must you add to complete the square?<br> x^2 + 2x = -1
Andru [333]
\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}


If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248


\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}

6 0
3 years ago
Read 2 more answers
The Experssion for 629​
Diano4ka-milaya [45]

iedikdtep-by-step explanation:

4 0
3 years ago
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