Answer:
and 
Step-by-step explanation:
The equation of curve is

We need to find the equation of the tangent line to the curve at the point (-3, 1).
Differentiate with respect to x.
![2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})](https://tex.z-dn.net/?f=2%5B2%28x%5E2%2By%5E2%29%5Cfrac%7Bd%7D%7Bdx%7D%28x%5E2%2By%5E2%29%5D%3D25%282x-2y%5Cfrac%7Bdy%7D%7Bdx%7D%29)

The point of tangency is (-3,1). It means the slope of tangent is
.
Substitute x=-3 and y=1 in the above equation.





Divide both sides by 130.

If a line passes through a points
with slope m, then the point slope form of the line is

The slope of tangent line is
and it passes through the point (-3,1). So, the equation of tangent is


Add 1 on both sides.


Therefore,
and
.
Answer:
They are not parallel
Step-by-step explanation:
original equation
10x + 3y = -3
subtract 10x
3y = -10x - 3
divide by 3
y = -10/3x - 1
original equation
5x - 4y = -3
subtract 5x
-4y = -5x-3
divide by -4
y = 5/4x + 3/4
the slopes are not equal to each other (5/4x and -10/3x) so they are not parallel
Answer:
it's 1/3
Step-by-step explanation:
5/6+(-1/2)
5/6-1/2
LCM= 6
(5-3)/6
2/6
1/3
Ax+bx−c=0
Step 1: Add c to both sides.
ax+bx−c+c=0+c
ax+bx=c
Step 2: Factor out variable x.
x(a+b)=c
Step 3: Divide both sides by a+b.
x(a+b)a+b=ca+b
x=ca+b