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tamaranim1 [39]
3 years ago
11

Prove: An odd times an odd equals an

Mathematics
1 answer:
solmaris [256]3 years ago
4 0

Answer:

See below

Step-by-step explanation:

(2m+1)(2n+1)

=4mn+2m+2n+1

=2(2mn+m+n)+1

=odd

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one factor of the function f(x) = x^3 -7x^2+14x-8 is (x-4). describe how to find the x intercept and the y intercepts of the gra
Xelga [282]

Answer:

(2 , 0)

(1 , 0)

(4 , 0)

(0, -8)

Step-by-step explanation:

f(x) = x³ -7x² + 14x - 8

The y intercept occurs when x = 0.

This means the first three terms all go to zero an the result is y = -8

As we are given one factor, (x - 4), we know that one zero will occur when this factor is zero

x - 4 = 0

x = 4

taking out the x - 4 term from the quadratic

x³ -7x² + 14x - 8 = (x² ± Cx + 2)(x - 4)

we can see that

2x ± 4Cx = 14x

±4C = 12

C = 12/±4 = ±3

also

±Cx² - 4x² = -7x²

±C - 4 = -7

so C = -3

(x² - 3x + 2)

(x - 2)(x - 1)

x = 2

x = 1

7 0
3 years ago
5 - 2(x+6) = 14 <br> Solve for x please help
LenKa [72]
5-2(x+6)=145-2x-12=14
-7-2x=14
-2x=21
-10.5
8 0
3 years ago
A new bank customer with 4,500 wants to open a money market account. The bank is offering a simple interest rate of 1.9. How muc
VikaD [51]

Answer:

$855

Step-by-step explanation:

The formula for simple interest is I = PRT where I is the interest paid/earned, P is the principal amount deposited/invested, R is the rate as a decimal, and T = time in years.

I = PRT

I = (4500)(0.019)(10)

I = $855

5 0
3 years ago
3. In the figure below, what is m 2 if m26 = 120°?
monitta

Answer:

C. 120°

Step-by-step explanation:

m \angle \: 2 = m \angle 6 \\ (corresponding \:  \angle s) \\  \\  \because \: m \angle 6 = 120 \degree \\  ...(given)\\  \\   \red{ \bold{\therefore \: m \angle 2 = 120 \degree }}

5 0
3 years ago
Is it possible for a 5×5 matrix to be invertible when its columns do not span set of real numbers R^5​? Why or why​ not? Select
xeze [42]

Answer:

The correct answer is A..

Step-by-step explanation:

From the Invertible Matrix Theorem (IMT) we have a set of equivalent conditions to determine if a square matrix is invertible or not. In particular, it says that a square matrix of dimension tex]n\times n[/tex] is invertible if and only if, its columns span the vector space tex]R^n[/tex].

In the particular case of this exercise we have a matrix of dimension tex]5\times 5[/tex]. So, by the Invertible Matrix Theorem its columns must span the vector space tex]R^5[/tex]. Now, according to the statement of the exercise this condition does not hold. Hence, the given matrix cannot be invertible.

5 0
3 years ago
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