Answer:
"Both students are correct. When light is traveling through small openings, solids, liquids, gases, or a vacuum, it behaves like a wave. When it interacts with matter, it acts like a stream of particles."
Explanation:
just got it right
Acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
because the object is slowing down, the acceleration will be negative.
acceleration = (4-34) / 60
acceleration = -30 / 60
acceleration = -0.5 m/s^2
answer : the train is accelerating at -0.5 m/s^2
Answer:
maybe c. because if you do 70
Explanation:
-50 you get 20 than you add that to the 25 and you get 45 and the nearest closest number is 47
Answer:
The net force on the car is 2560 N.
Explanation:
According to work energy theorem, the amount of work done is equal to the change of kinetic energy by an object. If '
' be the work done on an object to change its kinetic energy from an initial value '
' to the final value '
', then mathematically,
![W = K_{f} - K_{i} = \dfrac{1}{2}~m~(v_{f}^{2} - v_{i}^{2})........................................(I)](https://tex.z-dn.net/?f=W%20%3D%20K_%7Bf%7D%20-%20K_%7Bi%7D%20%3D%20%5Cdfrac%7B1%7D%7B2%7D~m~%28v_%7Bf%7D%5E%7B2%7D%20-%20v_%7Bi%7D%5E%7B2%7D%29........................................%28I%29)
where '
' is the mass of the object and '
' and '
' be the initial and final velocity of the object respectively. If '
' be the net force applied on the car, as per given problem, and '
' is the displacement occurs then we can write,
![W = F_{net}~.~s.......................................................(II)](https://tex.z-dn.net/?f=W%20%3D%20F_%7Bnet%7D~.~s.......................................................%28II%29)
Given,
.
Equating equations (I) and (II),
![&& - F_{net} \times 35~m = \dfrac{1}{2} \times 1400~Kg~\times(14^{2} - 18^{2})~m^{2}~s^{-2}\\&or,& F_{net} = \dfrac{\dfrac{1}{2} \times 1400~Kg~\times(14^{2} - 18^{2})}{35}~N\\&or,& F_{net} = 2560~N](https://tex.z-dn.net/?f=%26%26%20-%20F_%7Bnet%7D%20%5Ctimes%2035~m%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%201400~Kg~%5Ctimes%2814%5E%7B2%7D%20-%2018%5E%7B2%7D%29~m%5E%7B2%7D~s%5E%7B-2%7D%5C%5C%26or%2C%26%20F_%7Bnet%7D%20%3D%20%5Cdfrac%7B%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%201400~Kg~%5Ctimes%2814%5E%7B2%7D%20-%2018%5E%7B2%7D%29%7D%7B35%7D~N%5C%5C%26or%2C%26%20F_%7Bnet%7D%20%3D%202560~N)