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astra-53 [7]
3 years ago
6

Two students, Jordan and Taylor, are talking about light. Jordan says that light behaves as a stream of particles. Taylor declar

es that light behaves as a wave. Which student is correct?
Physics
1 answer:
FrozenT [24]3 years ago
3 0

Answer:

"Both students are correct. When light is traveling through small openings, solids, liquids, gases, or a vacuum, it behaves like a wave. When it interacts with matter, it acts like a stream of particles."

Explanation:

just got it right

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What information and measurements would you need to calculate the rate of movement?
aliina [53]
When you talk about rate, you will expect that it will be in terms of a time unit. It measures how fast it is going. So, you would expect that the denominator is in time units. For the movement, you can measure this with either distance or velocity.

So, for the first variety, you would need distance and time to measure the rate of how far you go at a certain time. It is also called as velocity. For the second variety, you would need velocity and time to measure the rate of how fast you are going at a certain interval. It is also called as acceleration.
8 0
4 years ago
Waves with higher amplitude transfer ____energy.
natali 33 [55]

Answer:

- Waves with higher amplitude transfer HIGHER energy.

- Waves with higher frequency transfer HIGHER energy.

3 0
3 years ago
Suppose a 96.10 kg hiker has ascended to a height of 1841 m above sea level in the process of climbing Mt. Washington. By what p
lbvjy [14]

Answer:

0.029%

Explanation:

Weight on the surface is given by,

F_W = mg = (96.1Kg)(9.8m/s^2)=941.78N

The acceleration due to gravity at given height is,

g_h=\frac{gR^2}{R+h^2}

The weight in another height is equal to

F_h=mg_h

F_h= m*\frac{gR^2}{R+h^2}

F_h = \frac{F_WR^2}{(R+h)^2}

F_h=\frac{(941.78)(6.371*10^6)}{(6.371*10^6+1841)}

F_h = 941.50N

The change of the Weight is,

\frac{F-F_h}{F}*100=\frac{941.78-941.50}{941.78}*100=0.029\%

6 0
3 years ago
How would you know if a force is acting on an object?​
Artemon [7]

Answer:

microscope

Explanation:

6 0
2 years ago
Read 2 more answers
Gravity is a force that every mass exerts on every other mass. When you jump up in the air, not only does the Earth exert a grav
sesenic [268]

Answer:

C. Your mass is very small compared to Earth's mass.

Explanation:

Newton's third law of motion states that:

"When an object A exerts a force (action force) on an object B, object B exerts an equal and opposite force (reaction force) on object A".

If we apply this law to the situation described in the problem, we see that:

- The action force is the gravitational force exerted by the Earth on you

- The reaction force is the gravitational force exerted by you on the Earth

And according to the 3rd law, the magnitude of the two forces is equal:

F_1 = F_2 (1)

We also know that, according to Newton's second law of motion, the force on an object is equal to the product between its mass (m) and its acceleration (a):

F=ma

So we can rewrite (1) as

ma = MA

where

m is the your mass

a is your acceleration

M is the Earth's mass

A is the Earth's acceleration

For the term on the left, we see that m is small, so a is larger (therefore, your acceleration is visible). However, for the term on the right, we see that the mass of the Earth is very large (M is very large), therefore, A is very small, which means that the acceleration of the Earth is almost negligible because the Earth's mass is very large.

4 0
4 years ago
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