60 ° is the angle between W- direction and the run direction.
You need the angle betwee S-direction and the run direction. This is 90° - 60° = 30 °.
By geometry you can trace a right triangle, where the S-component is the adyacent side and the run is the hypotenuse.
Then cos 30° = adyacent side / hypotenuse = S-component / run
Then S-component = run * cos 30° = 5.0 km * 0.866 = 4.3 km
Answer: 4.3 km
Answer:
Option C would be the correct alternative.
Explanation:
- An integrated programming program for arranging, evaluating, and saving analytical results seems to be a spreadsheet. Spreadsheets have been established as computerized analogs to worksheets for manual banking.
- There are various variables in something like a theoretical model that describes the structure being analyzed. By changing the variables as well as sometimes throughout combination while evaluating the outcome, analysis is performed.
The other choices offered aren't relevant to the existing contract below in the description section.
Answer:
0.38 m
Explanation:
As we know that the person due to the airbag action, comes to a complete stop, in a time of 36 msec or less, and during this interval, is decelerated at a constant rate of 60 g, we can find the initial velocity (when airbag starts to work), as follows:
vf = v₀ -a*t
If vf = 0, we can solve for v₀:
v₀ = a*t = 60*9.8 m/s²*36*10⁻³s = 21.2 m/s
With these values of v₀, a and t, we can find Δx, applying any kinematic equation that relates these parameters with the displacement.
Just for simplicity, we can use the following equation:
where vf=0, v₀ =21.2 m/s and a= -588 m/s².
Solving for d:
⇒ d = 0.38 m
Force is a vector quantity in which direction matters. This means that the forces will act in opposing directions so the net force will be
22.8 - 2.3 =
20.5 Newtons
Answer:
The magnitude of the car's acceleration as it slows during braking is 36.81 m/s²
Explanation:
From the question, the given values are as follows:
Initial velocity, u = 90 m/s
final velocity, v = 0 m/s
distance, s = 110 m
acceleration, a = ?
Using the equation of motion, v² = u² + 2as
(90)² + 2 * 110 * a = 0
8100 + 220a = 0
220a = -8100
a = -8100/220
a = -36.81 m/s²
The value for acceleration is negative showing that car is decelerating to a stop. The magnitude of the car's acceleration as it slows during braking is therefore 36.81 m/s²
