Can someone tell me what 5/9 + 4/6 = in fractions
1 answer:
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The Fundamental Theorem of Calculus regarding geometry states that
Where F is the indefinite integral of
The first step is to integrate
Then substitute the value of
and 
into 
![[2 (b)^{2}]-[2 (1)^{2}] = 240](https://tex.z-dn.net/?f=%5B2%20%28b%29%5E%7B2%7D%5D-%5B2%20%281%29%5E%7B2%7D%5D%20%3D%20240%20)
Hence the limit of the area under is between and
Where F is the indefinite integral of
The first step is to integrate
Then substitute the value of
Hence the limit of the area under
Answer:
1/36
Step-by-step explanation:
When the coefficient is 1, the function has zeros at -3 and -5, one horizontal unit from the vertex. You want to move the zero to (2, 0), which is 6 units from the vertex. To achieve a horizontal stretch by a factor of 6, the value of x in the function must be replaced by x/6. That would make the coefficient of x^2 be (1/6)^2 = 1/36.
The coefficient of the squared term is 1/36.
Answer:measurement of angle B is
Step-by-step explanation: