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3 years ago

Why is circle 1 similar to circle 2?

Mathematics

2 answers:

DanielleElmas [232]3 years ago

6 0

Answer: The answer is given below.

Step-by-step explanation: The given circles are:

Circle 1: centre (2, 3) and radius 4

Circle 2: centre (2, 3) and radius 12.

The equations of circle 1 and circle 2 are respectively given as :

$(x-2)^2+(y-3)^2=4^2,\\\\(x-2)^2+(y-3)^2=12^2.$

These two circles are drawn on the graph as shown in the attached figure.

We can easily see that the Circle 2 is a dilation of Circle 1 with a scale factor

$S=\dfrac{12}{4}=3.$

Thus, the two circles are similar.

raketka [301]3 years ago

5 0

The correct answer is

Circle 2 is a dilation of circle 1 with a scale factor of 3.

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3 years ago

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What is the solution to the equation 13.7y – 10.6 = 6.2y + 19.4?

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Answer:

Step-by-step explanation:

Simplifying

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Solving

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Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6.2y' to each side of the equation.

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Combine like terms: 6.2y + -6.2y = 0.0

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-10.6 + 7.5y = 19.4

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4 years ago

Through (4,-4) ; perpendicular to 6y=x-12

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y = mx + b

m = slope and b = y-intercept

We can arrange 6y = x - 12 in the form of y = mx + b

6y = x - 12

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Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

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To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

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3 years ago