Option 1
The equation of line in standard form passing through point (0, 5) is 5x – 9y = - 45
<u>Solution:</u>
Given that slope "m" = ![\frac{5}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D)
The lines passes through point (0, 5)
We have to write the equation of line in standard form
The standard form of an equation is Ax + By = C
Now first let use point slope form to find equation of line and then convert to standard form.
![\begin{array}{l}{\text { The point slope form is } y-y_{1}=m\left(x-x_{1}\right)} \\\\ {\text { Here } m=\frac{5}{9} ; x_{1}=0 ; y_{1}=5}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7B%20The%20point%20slope%20form%20is%20%7D%20y-y_%7B1%7D%3Dm%5Cleft%28x-x_%7B1%7D%5Cright%29%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20Here%20%7D%20m%3D%5Cfrac%7B5%7D%7B9%7D%20%3B%20x_%7B1%7D%3D0%20%3B%20y_%7B1%7D%3D5%7D%5Cend%7Barray%7D)
![\rightarrow y-5=\frac{5}{9}(x-0)](https://tex.z-dn.net/?f=%5Crightarrow%20y-5%3D%5Cfrac%7B5%7D%7B9%7D%28x-0%29)
Converting to standard form by rearranging terms,
9(y - 5) = 5(x – 0 )
9y – 45 = 5x
5x – 9y = - 45
Hence, the line equation is 5x – 9y = - 45, so option 1 is correct.