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Korvikt [17]
3 years ago
10

3.0

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Answer:

Solution given:

AD=1.8

AC=3.0

we have

∆ADC is a right angled triangle

Cos A=b/h

<A=cos-¹ (1.8/3)

<A=53.13°

again

∆ABC is a right angled triangle

Tan A=p/b=BC/AC

Tan 53.13×3=BC

BC=4

NOW

Area of triangle =½(AC*BC)=½(4×3)=6 <u>square </u><u>units</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>area</u><u>.</u>

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