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Korvikt [17]
2 years ago
10

3.0

Mathematics
1 answer:
Alex73 [517]2 years ago
3 0

Answer:

Solution given:

AD=1.8

AC=3.0

we have

∆ADC is a right angled triangle

Cos A=b/h

<A=cos-¹ (1.8/3)

<A=53.13°

again

∆ABC is a right angled triangle

Tan A=p/b=BC/AC

Tan 53.13×3=BC

BC=4

NOW

Area of triangle =½(AC*BC)=½(4×3)=6 <u>square </u><u>units</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>area</u><u>.</u>

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Bearings are tricky and I though I had this
Leya [2.2K]

Answer:

241°

Step-by-step explanation:

You are given the triangle internal angle (N) at Naples = 46°, and the side opposite a = 765 km. You are given the side b = 515 km, and asked to find an angle related to the internal angle opposite (C).

By the law of sines, the internal angle (C) at Canton is ...

sin(C)/b = sin(N)/a

C = arcsin((b/a)sin(N)) = arcsin(515/765·sin(46°)) ≈ 28.964°

The bearing from Elgin to Canton will be 270° less this angle, so is about 241°.

_____

Comment on your answer

Apparently, you added 29° to 270°, rather than subtracting. Since the direction from Elgin to Canton is south of west, the bearing angle must be between 180° and 270°. Note that a line west from Elgin will be parallel to the line east from Canton, so you can take advantage of alternate interior angles being congruent where the Elgin-Canton line crosses those parallel east-west lines.

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$157. 5

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The time it takes runners to complete a certain marathon are normally distributed with a mean of 4.6 hours and a standard deviat
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Add 4.6 to both sides:
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Simpfy 4 1/2+ 1 3/5 help
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Answer:

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Hi here’s the answers hope this helps

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