1 answer:
Answer:
Solution given:
AD=1.8
AC=3.0
we have
∆ADC is a right angled triangle
Cos A=b/h
<A=cos-¹ (1.8/3)
<A=53.13°
again
∆ABC is a right angled triangle
Tan A=p/b=BC/AC
Tan 53.13×3=BC
BC=4
NOW
Area of triangle =½(AC*BC)=½(4×3)=6 <u>square </u><u>units</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>area</u><u>.</u>
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X+y=27
x=2y
2y+y=27
y=9
x=27-y
x=27-9=18
Answer:
Step-by-step explanation:
The answer are will not and below
(a) a = 10.9 cm
(b) b = 20.78 cm
(c) c = 4.06 cm
<u>Explanation:</u>
(a)
height, h = 5cm
Hypotenuse, H = 12cm
Base, a = ?
Using pythagoras theorm:
(H)² = (h)² + (a)²
(12)² = (5)² + (a)²
119 = a²
a = 10.9 cm
(b)
Hypotenuse, H = 24 cm
Base, a = 12 cm
Height, b = ?
Using pythagoras theorm:
(H)² = (b)² + (a)²
(24)² = (b)² + (12)²
432 = b²
b = 20.78 cm
(c)
height, h = 4 cm
Hypotenuse, H = 5.7 cm
Base, c = ?
Using pythagoras theorm:
(H)² = (h)² + (c)²
(5.7)² = (4)² + (c)²
16.49 = c²
c = 4.06 cm
