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Readme [11.4K]
3 years ago
10

How to write composite number till 25 in set builder form Pls help

Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

All the natural numbers which are not prime numbers are composite numbers as they can be divided by more than two numbers (1 and itself).

Example: factors of 12

12 ÷1 = 12

12÷ 2 = 6

12÷3= 4

12÷4 = 3

12÷6=2

12÷12 = 1

= {12,6,4,3,2,1}

Composite Number/ Its Factors

4 = {1,2,4}

6 = {1,2,3,6}

8 = {1,2,4,8}

9 = {1,3,9}

10 = {1,2,5,10}

12 = {1,2,3,4,6,12}

14 = {1,2,7,14}

15 = {1,3,5,15}

16 = {1,2,4,8,16}

18 = {1,2,3,6,9,18}

20 = {1,2,4,5,10,20}

21 = {1,3,7,21}

22 = {1,2,11,22}

24 = {1,2,3,4,6,8,12,24}

25 = {1,5, 25}

Hope it helps!

#MissionExam001

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X-23 / x^2 -x- 20 - 2/5-x
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By simplifying \[x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x\] . This will result in a simplified version of  \[ - \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}\].

The Simplifying Algorithm is a wonderful way to simplify complex mathematics problems. It can be used to solve equations, convert fractions to decimals, and perform many other math operations. In this problem, the Simplifying Algorithm will help you reduce \[x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x\]

Since two opposites add up to 0, remove them from the expression.

\[ - \frac{{23}}{{{x^2}}} - \frac{{102}}{5} - x\]

Write all numerators above the least common denominator 5x2

\[ - \frac{{115 + 102{x^2} + 5{x^3}}}{{5{x^2}}}\]

Use the commutative property to reorder the terms so that constants on the left

\[\frac{{ - 5{x^3} - 115 - 102{x^2}}}{{5{x^2}}}\]

Rearrange the terms

\[\frac{{ - 5{x^3} - 102{x^2} - 115}}{{5{x^2}}}\]

By reording the terms

\[ - \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}\]

Hence, by simplifying this equation, divide both numerator and denominator. This will result in a simplified version of  \[ - \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}\].

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brainly.com/question/1542396

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