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Amiraneli [1.4K]
3 years ago
15

brllie rides her bike 176.25 miles in three weeks. she averaged 11.75 miles per hour each tim she ride. hiw many hours did it ta

ke her to ride 176.25 miles?
Mathematics
1 answer:
Goryan [66]3 years ago
7 0
176.25÷11.75=15 hours..........
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Walmart is selling 5 notebooks for $4.00. How much is it to buy 12 notebooks?
Anon25 [30]

Answer:

$9.60

Explanation:

4 divided by 5= 0.8

0.8 times 12= 9.6

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3 years ago
Immediately after giving birth, one woman weighed 177 pounds. She looses approcimately 4 lbs per month. Her goal is to get back
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163 lbs

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177 - 14lbs is 163

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Read 2 more answers
You want to rent an unfurnished one-bedroom apartment in Boston next year. The mean monthly rent for a random sample of 10 apart
Brilliant_brown [7]

Answer:

90% confidence interval: (2186.53;2881.47)

95% confidence interval: (2118.73;2949.27)

99% confidence interval: (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=2534 represent the sample mean  

\mu population mean (variable of interest)

\sigma=670 represent the population standard deviation

n=10 represent the sample size  

90% confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

2534-1.64\frac{670}{\sqrt{10}}=2186.53    

2534+1.64\frac{670}{\sqrt{10}}=2881.47

So on this case the 90% confidence interval would be given by (2186.53;2881.47)

95% confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

2534-1.96\frac{670}{\sqrt{10}}=2118.73    

2534+1.96\frac{670}{\sqrt{10}}=2949.27

So on this case the 95% confidence interval would be given by (2118.73;2949.27)

99% confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

2534-2.58\frac{670}{\sqrt{10}}=1987.37    

2534+2.58\frac{670}{\sqrt{10}}=3080.63

So on this case the 99% confidence interval would be given by (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

7 0
3 years ago
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