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Lana71 [14]
2 years ago
14

I don’t know how much by

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
7 0
Ed is heavier by 2.3 kg
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The amounts of a sum of money in 2 years and 5 years are rs 2800 and e 3250respectvely .find the sum
sammy [17]

Answer:

money : x

in 2 years : x+2

in 5years: x+2= 2800 + 3250

sum= x+2= 6050

x=6050÷2

x=3025

6 0
2 years ago
Which integer is closest to 0 on the number line?
IrinaVladis [17]

An integer is close to zero if it is "small".

By small, we mean that it is small in absolute value. In fact, for any given distance d, there are two integers that are d units away from zero: d and -d.

So, for example, -6 is close to zero than 8, because -6 is six units away from zero, while 8 is eight units away from zero.

So, the answer is B, -8, because it is 8 units away from zero. The other options A, C and D are, respectively, 12, 10 and 14 units away from zero.

8 0
2 years ago
10 to 7 power equals
Korolek [52]

Answer: 10,000,000

Step-by-step explanation: when anything rasied to the power you take what ever the Exponaten is and take how everything was there for example 10⁷ 10x10x10x10x10x10x10. And you multiply that.

6 0
3 years ago
Read 2 more answers
A cube has a volume of 800 cubic units. the length of the edge of this cube is between which two numbers?
8090 [49]
I set this up as an inequality, 800 \leq  s^{3}.  If you take the cubed root of 800, you get the lower bound of the side length, which is 9.2.  Then I just worked my way up until I hit the first number that put me over a volume of 800.  That number is 9.29, because 9.28 cubed is 799.1 (not high enough) and 9.29 cubed is 801.8.  Therefore, the bounds of the sides exist within a conjunction: 9.2\ \textless \ s\ \textless \ 9.29.  That's the best I could come up with to help on that one.  Wasn't sure if there was another method you were taught at school. I just used common sense more than any rule.
8 0
3 years ago
Given f(x)=4X+9, find the equation for f^-1(x)
Ilia_Sergeevich [38]

Answer:

4x+9 if that's not what u needed I can graph it for you too

6 0
3 years ago
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