If your asking to select all that apply,
The formula is arc length = θ ( r ) {\displaystyle {\text{arc length}}=\theta (r)} , where equals the measurement of the arc's central angle in radians, and r {\displaystyle r} equals the length of the circle's radius. Plug the length of the circle's radius into the formula.
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It’s beautiful because if you set up the problem as proportion and you put 3/106 over to you would have to multiply by 2×3 to get a six and 1×2 to get it to so it’s 2 mph
The value of x in the secants intersection is 1 units
The value of NM in the tangent and secant intersection is 51 units
<h3>How to find length when secant and tangent intersect?</h3>
The first question, two secant intersect outside the circle.
Therefore,
(6x + 8x)8x = (9 + 7)7
14x(8x) = 16(7)
112x² = 112
x² = 112 / 112
x = √1
x = 1
The second question, tangent and secant intersect,
Therefore,
(x + 3)² = (x - 3)(16 + x - 3)
(x + 3)² = (x - 3)(x + 13)
(x + 3)(x + 3) = (x - 3)(x + 13)
x² + 3x + 3x + 9 = x² + 13x - 3x - 39
x² + 9x + 9 = x² + 10x - 39
x² - x² + 9x - 10x = -39 - 9
-x = - 48
x = 48
NM = 48 + 3 = 51 units
learn more on secant and tangent here: brainly.com/question/12477905
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Answer:
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Step-by-step explanation:
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