we have the number
![6-\sqrt[]{-40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B-40%7D)
Remember that
i^2=-1
so
substitute
![6-\sqrt[]{(i^2)40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B%28i%5E2%2940%7D)
![6-2i\sqrt[]{10}](https://tex.z-dn.net/?f=6-2i%5Csqrt%5B%5D%7B10%7D)
therefore
the real part is 6
the imaginary part is -2√10
Perimeter of a parallelogram = 2(l+b)
= 2 (65+42)
= 2*107
= 214 cm
Step-by-step explanation:
step 1. The perimeter (P) is the length around the triangle.
step 2. P = 6 + 5 + L (the length of the hypotenuse)
step 3. L = sqrt(6^2 + 5^2) = sqrt(61) where sqrt is the square root
step 4. P = 11 + sqrt(61) = 18.81.
Pretty sure the correct answer is 9/25
Answer:
2×sqrt(6)×w⁷
Step-by-step explanation:
what I can read here, you need to simplify
sqrt(24×w¹⁴)
= sqrt(24)×sqrt(w¹⁴) = sqrt(4×6)×sqrt(w¹⁴) =
= 2×sqrt(6)×sqrt(w¹⁴)
and taking the square root of something with exponent simply means dividing that exponent by 2
so,
2×sqrt(6)×w⁷
