Solve these promblems but u have to estimate
5 1/9 + 1 7/8
11/20 - 5/8
8/9 + 2 13/15
2 answers:
5 1/9 rounds to 5
1 7/8 rounds to 2
5+2 = 7
11/20 rounds to 1
5/8 rounds to 1
1-1 = 0
8/9 rounds to 1
2 13/15 rounds to 3
1+3 = 4
5 1 / 9 + 1 7 / 8 = 6 + 1 / 9 + 7 / 8 = 6 + 8 / 72 + 63 / 72 = 6 + 71 / 72 ≈ 6,.98 round to tens( + 1 decimal place ) 7 ;
11 / 20 - 5 / 8 = 22 / 40 - 25 / 40 = -3 / 40 ≈ -0. 075 round to tens( + 1 decimal place ) - 0.1 ;
8 / 9 + 2 13 / 15 = 2 + 8 / 9 + 13 / 15 = 2 + 40 / 45 + 39 / 45 = 2 + 79 / 45 ≈ 3.75
round to tens( + 1 decimal place ) 3.8 ;
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Answer: The correct answer will be C. (Since the last comment got deleted smh)
Answer:
Option C is correct.
Step-by-step explanation:
Given Equation:
![\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B3b%5E3-2b%5E2-5%7D%3D%5Cfrac%7B2%7D%7Bb%5E3-2%7D)
To find: Solution of the Equation.
Consider,
![5(b^3-2)=2(3b^3-2b^2-5)](https://tex.z-dn.net/?f=5%28b%5E3-2%29%3D2%283b%5E3-2b%5E2-5%29)
![5b^3-10=6b^3-4b^2-10](https://tex.z-dn.net/?f=5b%5E3-10%3D6b%5E3-4b%5E2-10)
![6b^3-5b^3-4b^2+10-10=0](https://tex.z-dn.net/?f=6b%5E3-5b%5E3-4b%5E2%2B10-10%3D0)
![b^3-4b^2=0](https://tex.z-dn.net/?f=b%5E3-4b%5E2%3D0)
![b^2(b-4)=0](https://tex.z-dn.net/?f=b%5E2%28b-4%29%3D0)
b² = 0 ⇒ b = 0
b - 4 = 0 ⇒ b = 4
Therefore, Option C is correct.
Answer:
120
Step-by-step explanation:
Just add the 20 back to 40 and times by 2
40 + 20 = 60
60 * 2 = 120
we know that
![90 hundreds=90*100\\ =9,000](https://tex.z-dn.net/?f=%2090%20hundreds%3D90%2A100%5C%5C%20%3D9%2C000%20)
and
![one.thousand=1,000](https://tex.z-dn.net/?f=%20one.thousand%3D1%2C000%20)
So
Divide
by ![1,000](https://tex.z-dn.net/?f=%201%2C000%20)
![\frac{9,000}{1,000} =9](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%2C000%7D%7B1%2C000%7D%20%3D9%20)
therefore
the answer is
![9](https://tex.z-dn.net/?f=%209%20)
Answer:
c because c is c kkjwjwjjjwjwjsjssjsjjssmsswnsnsnsnnsns