Ask question

Ask question

All categories

julia-pushkina [17]

3 years ago

9

I just need some help with these im really struggling with these.

1 answer:

Nadusha1986 [10]3 years ago

3 0

Answer: I can't help you with the first part but maybe this will help on the second part-

Light behaves as a wave - it undergoes reflection, refraction, and diffraction just like any wave would. Yet there is still more reason to believe in the wavelike nature of light. Continue with Lesson 1 to learn about more behaviors that could never be explained by a strictly particle-view of light.

Sorry couldn't do better

Explanation:

You might be interested in

The SI unit of force is the

dexar [7]

The SI Measuring Unit for force is the Newton

6 0

3 years ago

The principal limitation of wind power is unpredictability.True or False

geniusboy [140]

True because you cannot see the wind

8 0

3 years ago

Read 2 more answers

If a wave has a frequency of 6 waves per second and a wavelength of 10 m, what is the wave's speed?

meriva

0.6 is the answer
Hope this helped

6 0

3 years ago

Food chains are made up of many_____________. HELP ASAP!!!!!

Mashcka [7]

Hello!

Possible answer could be Organisms

There are a lot of Organisms in the overall food chain.

Hope this helped!

4 0

4 years ago

Read 2 more answers

8. In the billiard ball room at the basement of Memorial Union, two identical balls are traveling toward each other along a stra

mel-nik [20]

Answer:

- Ball 1 will move backward at 7.89 m/s

- Ball 2 will move forward at 4.67 m/s

Explanation:

In an elastic collision, both the total momentum and the total kinetic energy of the system are conserved.

The conservation of the momentum can be written as:

$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where

$m_1$ is the mass of ball 1

$m_2$ is the mass of ball 2

$u_1$ is the initial velocity of ball 1

$u_2$ is the initial velocity of ball 2

$v_1$ is the final velocity of ball 1

$v_2$ is the final velocity of ball 2

The conservation of kinetic energy can be written as

$\frac{1}{2}m_1 u_2^2 + \frac{1}{2}m_2 u_2^2 = \frac{1}{2}m_1 v_1^2 + \frac{1}{2}m_2 v_2^2$

Working together the two equations, it is possible to find two expressions for the final velocities in terms of the initial velocities:

$v_1=\frac{m_1 -m_2}{m_1 +m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\\v_2=\frac{2m_1}{m_1+m_2}u_1 -\frac{m_1 -m_2}{m_1 +m_2}u_2$

In this problem we have:

$m_1 = m_2 = m$ since the mass of the two balls is identical

$u_1=+4.67 m/s$ is the initial velocity of ball 1

$u_2=-7.89 m/s$ is the initial velocity of ball 2

Substituting into the equations, we find the final velocities:

$v_1=\frac{2m}{m+m}u_2=u_2 =-7.89 m/s\\v_2=\frac{2m}{m+m}u_1=u_1=+4.67 m/s$

Therefore:

- Ball 1 will move backward at 7.89 m/s

- Ball 2 will move forward at 4.67 m/s

7 0

4 years ago