A. In what frame of reference does special relativity apply? b. In what frames must general relativity be used? c. Describe what
1 answer:
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Answer:
to the left
Explanation:
The magnitude of the electrostatic force between two charges is given by the following equation:
where:
is the Coulomb's constant
are the magnitude of the two charges
r is the distance between the two charges
Moreover, the force is:
- Attractive if the charges have opposite sign
- Repulsive if the charges have same sign
In this problem, we have:
is the magnitude of charge 1
is the magnitude of charge 2
r = 3 m is the distance between the two charges
Substituting, we find the force on both charges:
Here, the two charges are both positive, so the force is repulsive; since the 2 nC charge is on the left, this means that the force on this charge is to the left (away from the 5 nC charge).
Answer:
The frequency of the green light is
Explanation:
The visible region is part of the electromagnetic spectrum, any radiation of that electromagnetic spectrum has a speed of in the vacuum.
Green light is part of the visible region. Therefore, the frequency can be determined by the following equation:
(1)
Where c is the speed of light, is the wavelength and
is the frequency.
Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave (that is a magnetic field perpendicular to an electric field).
Then, can be isolated from equation 1
(2)
Notice that it is necessary to express the wavelength in units of meters.
⇒
Hence, the frequency of the green light is
Answer:
10 db
Explanation:
Detailed explanation and calculation is shown in the image below
