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konstantin123 [22]
2 years ago
15

A. In what frame of reference does special relativity apply? b. In what frames must general relativity be used? c. Describe what

happens to time and length at speeds close to the speed of light.
Physics
1 answer:
madam [21]2 years ago
8 0

Answer:special relativity apply to INERTIAL FRAME REFERENCE

Explanation:

inertial frame of reference is the one in which acceleration is zero this means object is moving with constant velocity

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An object 7 cm tall is placed at different locations in front of a concave mirror whose radius of curvature is 64 cm. Determine
cestrela7 [59]
The Asante was fhhbbd
3 0
3 years ago
A truck covers 40.0 m in 7.10 s while uniformly slowing down to a final velocity of 2.05 m/s.
Alona [7]

Answer:

(A) Original speed= 9.22 m/s

(B) Acceleration= -1.0099 m\s^2

Explanation:

A truck covers 40m in 7.10 secs

The truck slows down at a uniform velocity of 2.05 m/s

(A) The original speed can be calculated as follows

Vo= 2(40)/7.10 - 2.05

= 80/7.10 - 2.05

= 11.2676 - 2.05

= 9.22m/s

(B) The acceleration can be calculated as follows

a= Vf-Vo/t

= 2.05-9.22/7.10

= -7.17/7.10

= -1.0099m/s^2

5 0
3 years ago
Friction helps your vehicle stop quickly.<br> A. TRUE<br> B. FALSE
meriva

Answer:

true

Explanation:

4 0
2 years ago
Read 2 more answers
A mass of 10 g of oxygen fill a weighted piston–cylinder device at 20 kPa and 110°C. The device is now cooled until the tempe
mezya [45]

Answer:

The change of the volume of the device during this cooling is 14.3\times10^{-3}\ m^3

Explanation:

Given that,

Mass of oxygen = 10 g

Pressure = 20 kPa

Initial temperature = 110°C

Final temperature = 0°C

We need to calculate the change of the volume of the device during this cooling

Using formula of change volume

\Delta V=V_{2}-V_{1}

\Delta V=\dfrac{mR}{P}(T_{2}-T_{1})

Put the value into the formula

\Delta V=\dfrac{0.3125\times0.0821}{2.0265\times10^{9}}(383-273)

\Delta V=14.297\ L

\Delta V=14.3\times10^{-3}\ m^3

Hence, The change of the volume of the device during this cooling is 14.3\times10^{-3}\ m^3

6 0
3 years ago
A raging bull of mass 700 kg runs at 36 km/h .How much kinetic energy does it have ?
Ipatiy [6.2K]

Answer:

Use equation for kinetic energy: Ek=mV²/2

m=700 kg

V=10m/s

Ek=700kg*100m²7s²/2

Ek=35000 J=35kJ

Explanation:

Hope this helps you

Do mark me as brainliest

5 0
3 years ago
Read 2 more answers
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