Answer: 39.8 μC
Explanation:
The magnitude of the electric field generated by a capacitor is given by:

d is the distance between the plates.
For a capacitor, charge Q = CV where C is the capacitance and V is the voltage.

where A is the area of the plate and ε₀ is the absolute permittivity.
substituting, we get

It is given that the magnitude of the electric field that can exist in the capacitor before air breaks down is, E = 3 × 10⁶ N/C.
radius of the plates of the capacitor, r = 69 cm = 0.69 m
Area of the plates, A = πr² = 1.5 m²
Thus, the maximum charge that can be placed on disks without a spark is:
Q = E×ε₀×A
⇒ Q = 3 × 10⁶ N/C × 8.85 × 10⁻¹² F/m × 1.5 m² = 39.8 × 10⁻⁶ C = 39.8 μC.
Answer:
Snow
Explanation:
Precipitation is the formation of a solid after being a liquid. Snow, which is a solid, forms from water, a liquid.
Answer:pelo o que eu sei é ..
V
V
V
F
F
F
Explanation:
Answer:
A 1.5 metres per second squared B 0 C 6 0.5
b) 9m
Explanation:
a= v-a/t
a= acceleration measured in metres per second squared
v= final speed measured in metres per second
u= initial speed measured in metres per second
t= time measured in second
A
a=v-a/t
a= 3-0/2
a= 1.5 metres per second squared
Distance in a velocity time graph = area under
To calculate the distance in the first 4 seconds
You divide the graph into triangles and rectangles
Area A (triangle )= 1/2 × base × height
=1÷2 ×2×3
= 3m
Area B (rectangle)= L×B
=2×3
=6m
Area A + Area B= 3+6
= 9m
To solve this problem we will use the given expression and derive it in order to find the algebraic expressions of velocity and position. These equations will be similar to those already known in the cinematic movement but will be subject to the previously given function. We start deriving the equation for velocity


Integrate acceleration equation



At 
Replacing,

Therefore the value of the first Constant is

The expression can be escribed as,

Calculate the velocity after 6s,



Now using the same expression we can derive the equation for distance




At t=0, x=0

Therefore the value of the second constant is


Calculate the distance traveled after 11 s
At 

