Answer:
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
Explanation:
First, we analyze the final speed of Jim by using first equation of motion:
Vf₁ = Vi + at
where,
Vf₁ = final speed of Jim
Vi = initial speed of Jim = 0 m/s
a = acceleration of Jim
t = time of acceleration for Jim
Therefore,
Vf₁ = at ---------------- equation (1)
Now, we see the final speed of Joe. For Joe the parameters will become:
Vf = Vf₂
Vi = 0 m/s
a = a
t = 2t
Therefore,
Vf₂ = 2at
using equation (1):
<u>Vf₂ = 2 Vf₁</u>
<u>It shows that final speed of Joe is twice the final speed of Jim.</u>
Answer:
v=0.04m/s
Explanation:
To solve this problem we have to take into account the expression
where v and r are the magnitudes of the velocity and position vectors.
By calculating the magnitude of r and replacing w=0.02rad/s in the formula we have that
the maximum relative velocity is 0.04m/s
hope this helps!!
Its (a) and(a)for the other ? and the last one is (d)
Answer:
The conditions necessary for hearing the echo. The distance between the sound source and the reflecting surface must not be less than 17 metres where the time period between hearing the original sound and its echo should not be less than 0.1 of a second.
Answer:
A theory is a system of ideas intended to explain something, and a hypothesis is an educated guess.
Explanation: Hope this Helps! :)
