Question

The population of a pack of wolves is 88. The population is expected to grow at a rate of 2.5% each year.

Answer 1

Answer:

Option B is correct.

$f(t) = 88(1.025)^t$ represents the population of the pack of wolves after t years

Step-by-step explanation:

The exponential growth function is given by;

$f(t) = a(1+r)^t$               ......[1]

where

a represented the initial value

r represents the rate(in decimal)

t represents the time in years

As per the given statement: The population of a pack of wolves is 88. Also, the population is expected to grow at a rate of 2.5% each year.

⇒ a = 88 and  r =2.5% = 0.025.

Substituting these values in equation [1], we have;

$f(t) = 88(1+0.025)^t$

or

$f(t) = 88(1.025)^t$

Therefore, the population model of the pack of wolves after t years is given by:  $f(t) = 88(1.025)^t$