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MA_775_DIABLO [31]
3 years ago
7

Select three unit rates that can be used To describe the price of juice one dollar for 12 ounces $1.59 for a pint two dollars fo

r a quart and 299 for a gallon
Mathematics
1 answer:
enot [183]3 years ago
7 0

Answer:

$1.59 for a pint,

two dollars for a quart,

299 for a gallon

Step-by-step explanation:

Since, rate is used to compare different kinds of quantities and it is the ratio of the quantities,

Also, unit rate states the amount of first quantity corresponding to the unit amount of second quantity,

When we talk about the unit rates for a quantity,

Then it shows the price of the quantity per unit amount.

Thus, by the above explanation it is clear that,

The unit price for representing the price of juice would be,

$1.59 for a pint,

two dollars for a quart,

299 for a gallon.

Note : we do not consider 'one dollar for 12 ounces' a unit price because it is not the price per 1 ounce.

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Someone Help please!
salantis [7]
I think ur answer would be C.
8 0
3 years ago
if the side of a cube measures 1/3 ft, and there are 108 cubes in a box - with no gaps- what is the volume of the box?
Firlakuza [10]
Answer:108ft^3

Step by step solution: See photo

8 0
3 years ago
An item is priced at $13.94. If the sales tax is 4%, what does the item cost including sales tax?
oksano4ka [1.4K]

Answer:

$13.98

Step-by-step explanation:

Convert 4% into decimal = 0.04

Now...

13.94 + 0.04 = 13.98

6 0
3 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
4x – 8 = 12<br> 4x - 8 + 8 = 12 + 8<br> 4x = 20<br> 20<br> h
iogann1982 [59]
X=5, if that’s what you’re solving for
6 0
3 years ago
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