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2 years ago

Help i will give brainlist.

Mathematics

2 answers:

STatiana [176]2 years ago

8 0

Answer:

The third option

Step-by-step explanation:

Exponents are the little numbers up and to the right. None of the other options have a little number (exponent) of 4

Mekhanik [1.2K]2 years ago

4 0

Answer:

3m^4

Step-by-step explanation:

the third one

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I will give brainliest to person who answers correctly!

Crank

Answer:

41 is the answer .......

4 0

2 years ago

5. (03.02 MC)

inn [45]

Answer:

f(4) =2

Step-by-step explanation:

f(x) = 2х^2 - 30,

Let x=4

f(4) = 2 (4)^2 -30

= 2*16 -30

=32-30

= 2

6 0

2 years ago

In an injection-molding operation, the length and width, denoted as X and Y, respectively, of each molded part are evaluated. Le

nika2105 [10]

Answer:

attached below

Step-by-step explanation:

Attached below are the Venn diagrams

A : 48 < X < 52 cm

B : 9 < Y < 11 cm

a) A

b) A ∩ B

c) A' ∪ B

d) A ∪ B

e) for events to be mutually exclusive it means that both events can not occur simultaneously i.e. A ∩ B = 0

the process would not be successful hence the process would not produce parts with X = 50 cm and Y = 10 cm

6 0

2 years ago

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of analytical geometry is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$