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Annette [7]
3 years ago
14

Keith is the leading goal scorer for a team in an ice hockey league. Last season, he scored 42 goals in 82 games. Assuming he sc

ores goals at a constant rate, what is the slope of the line that represents this relationship if the number of games is along the x-axis and the number of goals is along the y-axis?
Mathematics
2 answers:
saul85 [17]3 years ago
8 0
Slope = rise / run

rise = change in y
run = change in x

slope = 42 goals / 82 games = 21/41 goals/game ≈ 0.51
Alex3 years ago
8 0

Answer: it’s 21/41 or A (I got a 100% on the test)

Step-by-step explanation:

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A number is randomly selected from {1, 2, 3, 4, 5, 6, 7, 8, 9, 10).
Katyanochek1 [597]

In this case, the complement would be selecting a number less than or equal to 7; the probability of this occurring is \boxed{\frac{7}{10}}.

7 0
3 years ago
1<br> x [4 + 6 x 3} - 9<br> Hurry solve
sweet [91]

Answer:

I know it is 13

Step-by-step explanation:

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After the price of petroleum oil went up by 10%, a consumer reduced his oil consumption by the same percent. By what percent wou
IgorLugansk [536]
Let's assign some random values to it, and say 1 unit of petroleum costs 100 bitcoins, because we all know bitcoins are the best currency :P

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7 0
4 years ago
Paddy and Anna each invest $2000 for 5 years.
Serga [27]

Answer: r= 1.22

Step-by-step explanation:

Formula for amount with simple interest = P(1+rt)

, where

P= principal value , r= rate of interest , t = time.

Given: P=  $2000, t= 5 years, r= 1.25% = 0.0125

A=2000(1+0.0125\times5)\\\\=2000(1.0625)=2125

Formula to compute compound amount : P(1+r)^t

=2000(1+r)^5

When both have same worth then

2000(1+r)^5=2125\\\\\\ (1+r)^5=\dfrac{2125}{2000}\\\\\\ (1+r)^5=1.0625

taking log on both sides , we get

5\ln (1+r)=\ln 1.0625\\\\\\ 5\ln (1+r)=0.0606246\\\\\\ \ln (1+r)=0.012125\\\\\\ 1+r=e^{0.005266}\\\\\\ 1+r=1.0122\\\\ r=0.0122\\\\ \\ r=1.22\%

Hence, Value of r= 1.22

6 0
3 years ago
Prove whether the quadrilateral is a parallelogram using the Distance &amp; Slope Formulas D(-5, -6), E(5, 2), F(4, -4), G(-6, -
amm1812

Answer:

See the distances bellow

Step-by-step explanation:

Given data

D(-5, -6), E(5, 2)

substitute into the expression for the distance

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((5+5)^2 + (2+6)^2)\\\\d= \sqrt((10)^2 + (8)^2)\\\\d= \sqrt(100 +64)\\\\d= \sqrt((164)\\\\d= 12.80

E(5, 2), F(4, -4)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((4-5)^2 + (-4-2)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08

F(4, -4), G(-6, -12)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6-4)^2 + (-12+4)^2)\\\\d= \sqrt((-10)^2 + (-8)^2)\\\\d= \sqrt(100+64)\\\\d= \sqrt((164)\\\\d= 12.80

G(-6, -12),  D(-5, -6)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6+5)^2 + (-12+6)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08

8 0
3 years ago
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