Answer:
SVI (Switched Virtual Interface)
Explanation:
For a switch to have an IP address, a switch virtual interface must be configured. This allows the switch to be managed remotely over the network.
Answer:
C Landscaper
Explanation:
From what I know about landscapers and from the description that makes the most sense.
IP Multimedia Subsystem<span> or </span>IP Multimedia<span> Core Network </span>Subsystem<span> (</span>IMS) is the term that refers and describes<span> an architectural framework for delivering IP multimedia services.
</span>IMS is a standards-based architectural framework <span> defined by the 3rd Generation Partnership Project (3GPP) </span>for delivering multimedia<span> communications </span>services such as voice, video and text .
A programming language that supports relational databases is SQL (Structured Query Language)
Structured Query Language (SQL), is the principal method for communicating with Relational Databases.
A relational database is a group of data elements that are linked together by predefined connections. These elements are laid up in the form of a series of tables containing columns and rows.
- Tables are utilized for storing data about the items that will be displayed in the database.
- A column in a database contains a specific type of data, whereas a field records the actual value of an attribute.
- The table's rows indicate a collection of linked values for a single item or entity.
Each entry in a database can be assigned a unique identity known as a primary key, and rows from other tables can be linked together via foreign keys. This data may be accessible in a variety of ways without having to reorganize the database tables itself.
Learn more about Relational Databases here:
brainly.com/question/8457395?referrer=searchResults
Answer:
PROGRAM QuadraticEquation
Solver
IMPLICIT NONE
REAL :: a, b, c
;
REA :: d
;
REAL :: root1, root2
;
//read in the coefficients a, b and c
READ(*,*) a, b, c
WRITE(*,*) 'a = ', a
WRITE(*,*) 'b = ', b
WRITE(*,*) 'c = ', c
WRITE(*,*)
// computing the square root of discriminant d
d = b*b - 4.0*a*c
IF (d >= 0.0) THEN //checking if it is solvable?
d = SQRT(d)
root1 = (-b + d)/(2.0*a) // first root
root2 = (-b - d)/(2.0*a) // second root
WRITE(*,*) 'Roots are ', root1, ' and ', root2
ELSE //complex roots
WRITE(*,*) 'There is no real roots!'
WRITE(*,*) 'Discriminant = ', d
END IF
END PROGRAM QuadraticEquationSolver
