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3 years ago

B+a=12 solve for B?

Mathematics

2 answers:

ivolga24 [154]3 years ago

8 0

B = 12 - a

Subtract a from both sides to isolate b, and you get the answer.

slega [8]3 years ago

5 0

Well, there is really not enough for this to be answered, so from an Algebra point of view, B=12-a. That is the ultimate answer you can get to with the information given. Are you sure there is nothing else on your paper/homework? Please let me know so I can finish with your question. Thank you!

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Is -54 rational number whole number or integersis

Yuki888 [10]

Answer:

-54 is a integer and rational number

Step-by-step explanation:

7 0

3 years ago

Bao is mixing flour and water to make dough the graph shows how much water he uses for different amounts of flour .How many lite

Allushta [10]

To know how many liters of water Bao use per liter of flour we have to divide the liters or flour so:

$\frac{1}{3}=0.33$

So Bao uses 0.33 or 1/3 of water per liter or flour

and to know hoy manu liters of flour Bao use per liter of water we have to made the oposite division so:

$\frac{3}{1}=3$

She use 3 liters of flour per liter of water

8 0

1 year ago

Drawing it out would be best can you help me please

leva [86]

Answer:

$z_1+z_2$ = (-2,5)

Step-by-step explanation:

To Find: $z_1+z_2$

Solution :

Referring the given graph

We can find the coordinates of $z_1$ and $z_2$

Coordinates of $z_1$ = (-7,1)

Coordinates of $z_2$ = (5,4)

Thus Coordinates of $z_1+z_2$ = (-7+5,1+4) = (-2,5)

Thus $z_1+z_2$ = (-2,5)

So, the point $z_1+z_2$ = (-2,5) is shown on the attached graph file

6 0

3 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago

noah saved $47 in june, $36 in july, and $27 in august. Then noah spent $18 on school supplies and $36 on new clothes. How much

Rashid [163]

$56
47 + 36 + 27 = 110
110 - 18 - 36 = 56

4 0

2 years ago