It is given that there are 41 males and 48 females in the small school.
So, the number of ways a male student can be chosen from 41 males is
Likewise, the number of ways a female student can be chosen from 48 females is .
Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:
Answer:
Step-by-step explanation:
A. The first inequality is graphed as a shaded area below the solid line with x-and y-intercepts of 7.5 and 5, respectively. The second inequality is graphed as a shaded area above the solid line with x- and y-intercepts of 3.
The solution set is the set of integer-valued grid points one or between the lines.
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B. The point (5, 1) is included in the solution area. Mathematically, it can be shown to satisfy the two inequalities:
2(5) +3(1) ≤ 15 ⇒ 13 ≤ 15 True
(5) +(1) ≥ 3 ⇒ 6 ≥ 3 True
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C. The point (5, 1) is in the solution set. It means Michael can purchase 5 sandwiches and 1 hot lunch within his budget constraints. That will provide 6 meals, which is more than the minimum of 3 that he wants to provide.
