With 21 marbles in the bag, and 9 of them green, her chances are 9/21 that she will pull a green marble. If you reduce 9/21 you get 3/7 which is the way the answer should be expressed (in lowest terms)

Answer Probability of green = 3/7

6 0

3 years ago

A person draws a card from a hat. Each card is one color with the following probabilities of being drawn: 1/10 for red, 1/5 for

Kay [80]

Answer:

$\dfrac{1}{4}$

Step-by-step explanation:

We are given that a card is drawn from a hat.

Probability that a red card is drawn, P(red) = $\frac{1}{10}$

Probability that a blue card is drawn, P(blue) = $\frac{1}{5}$

Probability that a black card is drawn, P(black) = $\frac{1}{20}$

Probability that a pink card is drawn, P(pink) = $\frac{1}{5}$

All these events are mutually exclusive i.e. they do not have anything in common.

For any two events A and B which are mutually exclusive, with probability P(A) and P(B), the probability that any one of the two events occur:

$P(A\cup B) = P(A) + P(B)$

Here event A can be thought of as drawing a blue card and

event B can be thought of as drawing a black card

So, P(blue or black) = P(blue) + P(black)

$\Rightarrow \dfrac{1}{5}+\dfrac{1}{20}\\\Rightarrow \dfrac{4+1}{20}\\\Rightarrow \dfrac{5}{20}\\\Rightarrow \dfrac{1}{4}$

So, the probability that a blue or black card is drawn from the hat:

$\dfrac{1}{4}$

8 0

3 years ago

The comma after "however" should be removed

Nadya [2.5K]

Answer:

No it shouldent

Step-by-step explanation:

Because it needs a comma

Example...

Howether, jhon had 5

8 0

3 years ago