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3 years ago

Write a related equation that has the variable on one side. Then simplify the other side.

Mathematics

1 answer:

BartSMP [9]3 years ago

3 0

Because 5 is being subtracted from 1 side, do the opposite and add it to both. 61 plus 5 = 66, so D is correct.

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10. You just hung a picture twelve inches above the wall trim. Your friend thinks the picture looks

muminat

Answer:

The angles measured between the shadow and the wall trim and the shadow and the top or bottom of the picture should be equal if the picture is level

Step-by-step explanation:

Whereby the picture is 12 inches above the wall trim and the Sun is casting a shadow on the wall, therefore, the edges of the shadow of a straight edged object is straight

If the picture is level, the shadow cast by the sun is transversal to the wall trim and the line formed by extending the bottom or top of the picture in the direction of the shadow. That is, if the picture is parallel, the shadow cast by the Sun on the wall is transversal to the picture and the wall trim if or when the shadow eventually crosses the picture

With the protractor, the angle between the shadow and the wall trim and the shadow and the top or bottom is measured

The angles measured should be the same if the picture is level.

5 0

3 years ago

Helppppp question 21,22

Anna35 [415]

21. B or 6

22. B or 2a/h

3 0

1 year ago

Which Of the following is the solution to 4|x+3|>8?

Shalnov [3]

Too bad you haven't shared illustrations of the possible solutions.

Starting with 4|x+3|>8, div. both sides by 4: <span>|x+3|>2

Case 1: x+3 is already positive: then x+3>2, or x > -1

Case 2: x+3 is negative: Then -(x+3)>2, or -x - 3 > 2, or -5>x or x<-5

Draw a number line representing x values. Place empty circles at x = -5 and x = -1. Draw a vector from the circle at x = -1, to the right of x = -1. Draw a vector from the circle at x = - 5, to the left of x = -5. Note that x values between x = -5 and x = -1 are not solutions.</span>

5 0

2 years ago

Write a quadratic equation with 0, -8

Ludmilka [50]

If 0, and -8 are the roots of the quadratic equation we can write
(x-0)(x+8)=0
x(x+8)=0
x²-8x=0

4 0

3 years ago

Two coworkers commute from the same building. They are interested in whether or not there is any variation in the time it takes

jenyasd209 [6]

Answer:

Step-by-step explanation:

Hello!

You have two samples.

Sample 1 (time that takes one commute of worker 1)

n₁= 20

S₁²= 12.2

Sample 2 (time that takes one commute of worker 2)

n₂= 20

S₂²= 16.9

The hypothesis is that the first coworker is more consistent with his commute times, this means that the variability of his commute times is less than the variability of the commute times of worker 2. With this in mind, the hypothesis for a variance ratio test is:

H₀: σ₁² ≥ σ₂²

H₁:: σ₁² < σ₂²

α: 0.10

The statistic for this test is:

F= (S₁²/S₂²) * (σ₁²/σ₂²) ~ F $_{n1-1;n2-1}$

The test is one-tailed (left) with just one critical value:

$F_{n_1-1;n_2-1;\alpha } = \frac{1}{F_{n_2-1;n_1-1;1-\alpha }} = \frac{1}{F_{19;19;0.90}} = \frac{1}{1.82} =0.549$

(The F-table I use only has the values for high probabilities so I've used a conversion method to obtain the value for the small probability)

Your decision rule is:

If F ≤ 0.549, you reject the null hypothesis.

if F > 0.549, you support the null hypothesis.

The calculated value:

F= (S₁²/S₂²) * (σ₁²/σ₂²) = (12.2/16.9) * 1= 0.722

Since the calculated F-value is greater than the critical value, the decision is to not reject the null hypothesis. So you can say that the variability of the commute times of worker 1 is less than the variability of the commute times of worker 2.

I hope you have a SUPER day!

7 0

3 years ago