1) (2i-4)-(6i+9) = 2i-4-6i-9 = -4i-13
2) (-3+8i)+(3-8i) = -3+8i+3-8i = 0+0i = 0
I'm sorry but do you ha e a picture of a flowchart
The only expressions that are correctly factored are;
A) 16a⁵ - 20a³ = 4a³(4a² - 5)
B) 24a⁴ + 18 = 6(4a⁴ + 3)
C) 12a³ + 8a = 4a(3a² + 2)
D) 30a⁶ - 24a² = 3a²(10a⁴ - 8)
<h3>How to factorize equations?</h3>
1) 16a⁵ - 20a³
To factorize this, we will have to get out the common factor first. The common factor is 4a³. Thus, we now have;
4a³(4a² - 5)
2) 24a⁴ + 18
To factorize this, we will have to get out the common factor first. The common factor is 6. Thus, we now have;
6(4a⁴ + 3)
3) 12a³ + 8a
To factorize this, we will have to get out the common factor first. The common factor is 4a. Thus, we now have;
4a(3a² + 2)
4) 30a⁶ - 24a²
To factorize this, we will have to get out the common factor first. The common factor is 3a². Thus, we now have;
3a²(10a⁴ - 8)
Read more about factorization of equations at; brainly.com/question/723406
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Answer:
The child can sell 15 cookies and 30 lemonade glasses, or 10 cookies and 40 glasses of lemonade, etc
Step-by-step explanation:
If the child wants to make $30 and gets $1 per cookie and $0.50 per lemonade glass, he could sell 15 cookies and 30 glasses, 10 cookies and 40 glasses, etc. He has to sell at least 5 cookies, though, as the lemonade is only worth $25.
No they cannot because 3 is way to short
