Answer:
0.37
Step-by-step explanation:
we have given that emails arrives at the server at the rate of 10 per hour means 
per minute
we have to find the probability that the time difference between the two email is more than 2 minute
so probability 
<span>Defective rate can be expected
to keep an eye on a Poisson distribution. Mean is equal to 800(0.02) = 16,
Variance is 16, and so standard deviation is 4.
X = 800(0.04) = 32, Using normal approximation of the Poisson distribution Z1 =
(32-16)/4 = 4.
P(greater than 4%) = P(Z>4) = 1 – 0.999968 = 0.000032, which implies that
having such a defective rate is extremely unlikely.</span>
<span>If the defective rate in the
random sample is 4 percent then it is very likely that the assembly line
produces more than 2% defective rate now.</span>
1 x
---- = -----
8 1224
8x = 1224
x = 153
The domain the given graph is :
- -12 <u><</u> x <u><</u> 13
