Is 70thounsand written in standard form or word form?explain

Mathematics

1 answer:

Burka [1]2 years ago

3 0

Answer:

It is a mixture of the two.

Step-by-step explanation:

Standard form would be 70,000

Word form would be seventy thousand

You might be interested in

Why is the answer B?

Radda [10]

Remark

Whatever the original price, he gets 70% in the first instance.

He gets 80% in the second instance.

He gets 90% in the third instance

His total income is 240 dollars.

Let the original price be x

Equation

70%x + 80%x +90%x = 240

70% = 0.7 ; 80% = 0.8 ;90% = 0.9

Solution

0.7x + 0.8x + 0.9x = 240 Take out x as a common factor and add the decimals.

x (0.7 + 0.8 + 0.9) = 240

2.4x = 240 Divide both sides by 2.4

x = 240/2.4

x = 100

So the watches should have brought in 3*100 = 300 dollars.

He only brought in 240 dollars.

He lost 300 - 240 = 60 dollars.

The answer is B.

7 0

2 years ago

12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$