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beks73 [17]
3 years ago
10

A formula for finding P, the perimeter of a rectangle, is P = 2l + 2w, where l is the length of the rectangle, and w is its widt

h.
What is P when l = 10 centimeters and w = 5 centimeters?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
4 0

Answer:

P=30cm

Step-by-step explanation:

So the formula there is to find the Perimeter of the rectangle, so we are going to use it!

Using Substitution:

A=2L+2W\\A=2(10)+2(5)\\A=20+10\\A=30

Hope this helps!

Stay Safe!

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Answer:

Step-by-step explanation:

487 is a prime, because 487 is only divided by 1 or by itself

5 0
2 years ago
For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

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Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

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Answer:

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Step-by-step explanation:

We can use the distributive property to expand:

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