Answer:
At 11:00 am the both trains will be at same distance away from Roseville
Step-by-step explanation:
The first train was 40 miles away from Roseville at 7:00 am
After some time t the both trains will be at the same distance away from Roseville.
We will make equation for that situation
d- distance v1= 40mph and v2= 50mph - velocity
d = v1*t + 40 = v2*t => v2*t - v1*t = 40 => t (v2-v1) = 40 -> t = 40/ (v2-v1)
t = 40/(50-40) = 40/10= 4h t = 4h
7:00 am * 4h = 11:00 am
Good luck!!!
Answer:
option-C
terminal
Step-by-step explanation:
We know that
reference angle is between terminal side and x-axis
so, the other side will be terminal position
so, we can write as
The positive acute angle formed by the <u>terminal</u> side of an angle in standard position and the x-axis is called a reference angle.
So,
option-C
terminal
Draw a diagram to illustrate the problem as shown in the figure below.
Let h the height of the hill. =
At position A, the angle of elevation is 40°, and the horizontal distance to the foot of the hill is x.
By definition,
tan(40°) = h/x h = x tan40 = 0.8391x
(1)
At position B, Joe is (x - 450) ft from the foot of the hill. His angle of elevation is
40 + 18 = 58°.
By definition, tan(58°) = h/(x - 450)
h = (x - 450) tan(58°) = 1.6003(x-450)
h = 1.6003x - 720.135 (2)
Equate (1) and (2).
1.6003x - 720.135 = 0.8391x 0.7612x = 720.135
x = 946.0523
From (1), obtain
h = 0.8391*946.0523 = 793.8 ft
Answer: The height of the hill is approximately 794 ft (nearest integer)
60×120=7200
7200÷100=72
60+72=132
answer=£132
hope this helps.....
