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3 years ago

HELP ME ASAP WITH MATH MONEY & WAGES

Mathematics

2 answers:

Sever21 [200]3 years ago

7 0

Answer:

96,220

Step-by-step explanation:

187,400 x 0.3 = 56,220

56220+40000= 96,220

hope this helps, have a great day :)

Dennis_Churaev [7]3 years ago

5 0

Answer:

96,220

Step-by-step explanation:

187,400 x .3 (30%)= 56,220

56220+40000= *96,220

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A circle has radius 50 cm. Which of these is closest to its area?

Angelina_Jolie [31]

Answer:

7854 square centimeters

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

A = pi ( 50)^2

A = 2500 pi

Let pi be approximated by 3.14

A = 2500 * 3.14

A =7850 cm^2

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Luis, Marlon, and Victoria are counting money. They each have the same amount in dollar bills, quarters, dimes, nickels, and pen

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3 years ago

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What is 4 9/10 expressed as a decimal? Enter your answer in the box.

soldier1979 [14.2K]

Answer:

4.9 is decimal form.

Step-by-step explanation:

4 9/10

Solve :

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= 49/10

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2 years ago

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A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg

polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

$P(X = x) = nCx p^{x} q^{n - x}$

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662$

Finally, the probability that 2 or fewer students will withdraw is

$P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355$

b) Compute the probability that exactly 4 will withdraw.

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304$

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716$

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

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3 years ago

José vende dos bicicletas, cada una a 198 soles. Si en una ganó el 10% y en la otra perdió el 10%. ¿Cuanto ganó o perdió pir la

Arte-miy333 [17]

Answer:

I win 10% = 217.8

I lost 10% = 178.2

217.8 + 178.2 = 396

198 + 198 = 396

396 = 396

I neither gain nor lose anything: V

Step-by-step explanation:

3 0

2 years ago