Question

A coin is flipped and a random marble is picked from a bag of 10 marbles. Two of the marbles in the bag are red. What is the probability of the coin landing on tail and a red marble being drawn?

Answer 1

Answer:

$\frac{1}{10}$ is the probability of the coin landing on tail and a red marble being drawn.

Step-by-step explanation:

Given A coin is flipped and a random marble is picked from a bag of 10 marbles. Two of the marbles in the bag are red. we have to find the probability of the coin landing on tail and a red marble being drawn.

P(a red marble)=$\frac{No.\thinspaceof\thinspace red\thinspace marbles}{Total\thinspace marbles}$

                        =$\frac{2}{10}$

P(getting a tail)=$\frac{1}{2}$

Since both events are independent.

∴ P(he coin landing on tail and a red marble being drawn)

 =$P(getting\thinspace a\thinspace tail)\times P(a\thinspace red\thinspace marble\thinspace drawn)$

 =$\frac{2}{10}\times \frac{1}{2}$

 = $\frac{1}{10}$

Hence, $\frac{1}{10}$ is the probability of the coin landing on tail and a red marble being drawn.